tan^-1(1)=x を解きます| Microsoft 数学ソルバー

x を解く

x = \frac{200000000000000000}{3491012985643517} = 57\frac{1012259818319531}{3491012985643517} \approx 57.289961631

線形方程式を解くための手順

\tan ^ { - 1 } ( 1 ) = x

問題内の三角関数の値を求める

0.017455064928217585 ^ {-1} = x

0.017455064928217585 の -1 乗を計算して \frac{200000000000000000}{3491012985643517} を求めます。

\frac{200000000000000000}{3491012985643517}=x

すべての変数項が左辺にくるように辺を入れ替えます。

x=\frac{200000000000000000}{3491012985643517}

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Trigonometry

次に類似した 5 個の問題:

\tan ^ { - 1 } ( 1 ) = x

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\newcommand{\+}{^{\dagger}} \newcommand{\angles}[1]{\left\langle\, #1 \,\right\rangle} \newcommand{\braces}[1]{\left\lbrace\, #1 \,\right\rbrace} \newcommand{\bracks}[1]{\left\lbrack\, #1 \,\right\rbrack} \newcommand{\ceil}[1]{\,\left\lceil\, #1 \,\right\rceil\,} \newcommand{\dd}{{\rm d}} \newcommand{\down}{\downarrow} \newcommand{\ds}[1]{\displaystyle{#1}} \newcommand{\expo}[1]{\,{\rm e}^{#1}\,} \newcommand{\fermi}{\,{\rm f}} \newcommand{\floor}[1]{\,\left\lfloor #1 \right\rfloor\,} \newcommand{\half}{{1 \over 2}} \newcommand{\ic}{{\rm i}} \newcommand{\iff}{\Longleftrightarrow} \newcommand{\imp}{\Longrightarrow} \newcommand{\isdiv}{\,\left.\right\vert\,} \newcommand{\ket}[1]{\left\vert #1\right\rangle} \newcommand{\ol}[1]{\overline{#1}} \newcommand{\pars}[1]{\left(\, #1 \,\right)} \newcommand{\partiald}[3][]{\frac{\partial^{#1} #2}{\partial #3^{#1}}} \newcommand{\pp}{{\cal P}} \newcommand{\root}[2][]{\,\sqrt[#1]{\vphantom{\large A}\,#2\,}\,} \newcommand{\sech}{\,{\rm sech}} \newcommand{\sgn}{\,{\rm sgn}} \newcommand{\totald}[3][]{\frac{{\rm d}^{#1} #2}{{\rm d} #3^{#1}}} \newcommand{\ul}[1]{\underline{#1}} \newcommand{\verts}[1]{\left\vert\, #1 \,\right\vert} \newcommand{\wt}[1]{\widetilde{#1}} ...

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クリップボードにコピー済み

0.017455064928217585 ^ {-1} = x

問題内の三角関数の値を求める

\frac{200000000000000000}{3491012985643517}=x

0.017455064928217585 の -1 乗を計算して \frac{200000000000000000}{3491012985643517} を求めます。

x=\frac{200000000000000000}{3491012985643517}

すべての変数項が左辺にくるように辺を入れ替えます。

例

二次方程式の公式

{ x } ^ { 2 } - 4 x - 5 = 0

三角法

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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

連立方程式

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

積分法

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

限界

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

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