{l}{y^2-2y+x=x}{frac{sqrt{x}+y}{e-1}=2^e+1} を解きます| Microsoft 数学ソルバー

$$\left. \begin{array} { l } { y ^ { 2 } - 2 y + x = x } \\ { \frac { \sqrt { x } + y } { e - 1 } = 2 ^ { e + 1 } } \end{array} \right.$$

y,x を解く (複素数の解)

$$x=4^{e+1}\left(1-e\right)^{2}\approx 511.466884353-1.252732566 \cdot 10^{-13}i\text{, }y=0$$

$$x=4\left(-e\times 2^{e}+2^{e}+1\right)^{2}\approx 425.004349845-1.040960433 \cdot 10^{-13}i\text{, }y=2$$

y,x を解く

$$x=4^{e+1}\left(1-e\right)^{2}\approx 511.466884353\text{, }y=0$$

$$x=4\left(-e\times 2^{e}+2^{e}+1\right)^{2}\approx 425.004349845\text{, }y=2$$