Solve 4/12*9/8 | Microsoft Math Solver

Evaluate

\frac{3}{8} = 0.375

Factor

\frac{3}{2 ^{3}} = 0.375

Quiz

Arithmetic

5 problems similar to:

\frac{4}{1 2} \times \frac{9}{8}

Similar Problems from Web Search

How do you evaluate

\frac{2}{1 2} \times \frac{2}{5}

https://socratic.org/questions/how-do-you-evaluate-frac-2-12-times-frac-2-5

\frac{2}{1 2} \times \frac{2}{5} = \frac{4}{6 0}

Explanation: When multiplying fractions, multiply the numerators together, and multiply the denominators together.

\frac{2 \times 2}{1 2 \times 5} = \frac{4}{6 0}

What is

\frac{2}{3} \times \frac{7}{8}

https://socratic.org/questions/what-is-2-3-times-7-8

\frac{1 4}{2 4}

\frac{7}{1 2}

Explanation: To solve this following the rules for multiplying fractions you multiply the numerators and the denominators:

\frac{2}{3} \times \frac{7}{8} \to \frac{2 \times 7}{3 \times 8} \to \frac{1 4}{2 4}

...

How do you find the product

\frac{1}{2} \times \frac{2}{8}

https://socratic.org/questions/how-do-you-find-the-product-1-2-times2-8

\frac{1}{8}

Explanation: First, we can cancel common terms in the numerator and denominator:

\frac{1}{2} \times \frac{2}{8} = \frac{1}{( 2 )} \times \frac{( 2 )}{8} = \frac{1}{1} \times \frac{1}{8}

...

How do you write the answer

\frac{5}{1 2} \times \frac{2 4}{2 5}

in simplest form?

https://socratic.org/questions/how-do-you-write-the-answer-5-12-times-24-25-in-simplest-form

\frac{2}{5}

Explanation:

\frac{5}{1 2} \times \frac{2 4}{2 5}

\frac{5 1}{1 2} \times \frac{2 4}{5 5}

\frac{2 4}{1 2 \cdot 5}

...

{1 / 2} \times (1 / 2, 1]

is not open in the ordered square [duplicate]

https://math.stackexchange.com/q/2902076

Suppose

p = (\frac{1}{2}, 1)

is an interior point of

{\frac{1}{2}} \times (\frac{1}{2}, 1]

. As

p

is not an endpoint of

[0, 1] \times [0, 1]

in the lexicographic order, a local base for its neighbourhoods are ...

A factory makes three types of biased coins with probability of getting head when tossed is

\frac{1}{2}

\frac{1}{3}

\frac{1}{4}

respectively

https://math.stackexchange.com/questions/1662720/a-factory-makes-three-types-of-biased-coins-with-probability-of-getting-head-whe

Your last remark is indeed correct. The probability you calculated is

P (H \cap H_{M})

, the probability that a coin from those 3 has its head marked and comes up

H

P (H) = \frac{1}{3} (\frac{1}{2} + \frac{1}{3} + \frac{1}{4}) = \frac{1 3}{3 6}

...

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\frac{1}{3}\times \left(\frac{9}{8}\right)

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

\frac{1\times 9}{3\times 8}

Multiply \frac{1}{3} times \frac{9}{8} by multiplying numerator times numerator and denominator times denominator.

\frac{9}{24}

Do the multiplications in the fraction \frac{1\times 9}{3\times 8}.

\frac{3}{8}

Reduce the fraction \frac{9}{24} to lowest terms by extracting and canceling out 3.

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