Solve 4/12+9/8*15/3-26/10

$$\frac{ 4 }{ 12 } + \frac{ 9 }{ 8 } \times \frac{15}{3} - \frac{26}{10}$$

Evaluate

$$\frac{403}{120}\approx 3.358333333$$

Solution Steps

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}+\frac{9}{8}\times \left(\frac{15}{3}\right)-\frac{26}{10}$$

Divide 15 by 3 to get 5.

$$\frac{1}{3}+\frac{9}{8}\times 5-\frac{26}{10}$$

Express \frac{9}{8}\times 5 as a single fraction.

$$\frac{1}{3}+\frac{9\times 5}{8}-\frac{26}{10}$$

Multiply 9 and 5 to get 45.

$$\frac{1}{3}+\frac{45}{8}-\frac{26}{10}$$

Least common multiple of 3 and 8 is 24. Convert \frac{1}{3} and \frac{45}{8} to fractions with denominator 24.

$$\frac{8}{24}+\frac{135}{24}-\frac{26}{10}$$

Since \frac{8}{24} and \frac{135}{24} have the same denominator, add them by adding their numerators.

$$\frac{8+135}{24}-\frac{26}{10}$$

Add 8 and 135 to get 143.

$$\frac{143}{24}-\frac{26}{10}$$

Reduce the fraction \frac{26}{10} to lowest terms by extracting and canceling out 2.

$$\frac{143}{24}-\frac{13}{5}$$

Least common multiple of 24 and 5 is 120. Convert \frac{143}{24} and \frac{13}{5} to fractions with denominator 120.

$$\frac{715}{120}-\frac{312}{120}$$

Since \frac{715}{120} and \frac{312}{120} have the same denominator, subtract them by subtracting their numerators.

$$\frac{715-312}{120}$$

Subtract 312 from 715 to get 403.

$$\frac{403}{120}$$

Factor

$$\frac{13 \cdot 31}{2 ^ {3} \cdot 3 \cdot 5} = 3\frac{43}{120} \approx 3.358333333$$