Microsoft Math Solver
Solve
Practice
Download
Solve
Practice
Topics
Pre-Algebra
Mean
Mode
Greatest Common Factor
Least Common Multiple
Order of Operations
Fractions
Mixed Fractions
Prime Factorization
Exponents
Radicals
Algebra
Combine Like Terms
Solve for a Variable
Factor
Expand
Evaluate Fractions
Linear Equations
Quadratic Equations
Inequalities
Systems of Equations
Matrices
Trigonometry
Simplify
Evaluate
Graphs
Solve Equations
Calculus
Derivatives
Integrals
Limits
Algebra Calculator
Trigonometry Calculator
Calculus Calculator
Matrix Calculator
Download
Topics
Pre-Algebra
Mean
Mode
Greatest Common Factor
Least Common Multiple
Order of Operations
Fractions
Mixed Fractions
Prime Factorization
Exponents
Radicals
Algebra
Combine Like Terms
Solve for a Variable
Factor
Expand
Evaluate Fractions
Linear Equations
Quadratic Equations
Inequalities
Systems of Equations
Matrices
Trigonometry
Simplify
Evaluate
Graphs
Solve Equations
Calculus
Derivatives
Integrals
Limits
Algebra Calculator
Trigonometry Calculator
Calculus Calculator
Matrix Calculator
Solve
algebra
trigonometry
statistics
calculus
matrices
variables
list
Solve for a
a=\frac{bc}{3},b\neq 0
View solution steps
Steps for Solving Linear Equation
\frac{3a}{b}=c
Multiply both sides of the equation by b.
3a=cb
The equation is in standard form.
3a=bc
Divide both sides by 3.
\frac{3a}{3}=\frac{bc}{3}
Dividing by 3 undoes the multiplication by 3.
a=\frac{bc}{3}
Solve for b
\left\{\begin{matrix}b=\frac{3a}{c}\text{, }&a\neq 0\text{ and }c\neq 0\\b\neq 0\text{, }&c=0\text{ and }a=0\end{matrix}\right.
View solution steps
Steps for Solving Linear Equation
\frac{3a}{b}=c
Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by b.
3a=cb
Swap sides so that all variable terms are on the left hand side.
cb=3a
Divide both sides by c.
\frac{cb}{c}=\frac{3a}{c}
Dividing by c undoes the multiplication by c.
b=\frac{3a}{c}
Variable b cannot be equal to 0.
b=\frac{3a}{c}\text{, }b\neq 0
Quiz
Linear Equation
5 problems similar to:
\frac{3a}{b}=c
Similar Problems from Web Search
If \displaystyle\frac{{a}}{{b}}=\frac{{4}}{{3}} and \displaystyle\frac{{b}}{{c}}=\frac{{2}}{{3}} , what is the value of \displaystyle{2}\frac{{b}}{{a}}+{b}-{c} ?
https://socratic.org/questions/if-a-b-4-3-and-b-c-2-3-what-is-the-value-of-2b-a-b-c
See below. Explanation: Since \displaystyle\frac{{a}}{{b}}=\frac{{4}}{{3}} , then \displaystyle\frac{{b}}{{a}}=\frac{{3}}{{4}} . Since \displaystyle\frac{{b}}{{c}}=\frac{{2}}{{3}} , \displaystyle{3}{b}={2}{c} ...
Prove that every positive integer less than or equal to the square root of a is a near factor of a
https://math.stackexchange.com/questions/1398952/prove-that-every-positive-integer-less-than-or-equal-to-the-square-root-of-a-is
Let k be a positive integer with k\le\sqrt{a}. Use the division algorithm to write a=kq+r where 0\le r <k. Note that q\ge k (this follows since k\cdot k\le a, so the quotient in dividing a ...
How to prove this relation
https://math.stackexchange.com/q/2088382
I see my mistake and I do believe this is the correct solution \begin{align} \frac{a}{b} &= \frac{c}{d} \\ &= (cd^{-1}) \cdot (bb^{-1}) \cdot (kk^{-1}) \\ &= (cb) \cdot (d^{-1}b^{-1}) \cdot (kk^{-1}) \\ &= (ad) \cdot (d^{-1}b^{-1}) \cdot (kk^{-1}) \\ &= (ab^{-1}) \cdot (dd^{-1}) \cdot (kk^{-1}) \\ &= (ab^{-1}) \cdot (kk^{-1}) \\ &= (\frac{a}{b}) \cdot (\frac{k}{k}) \\ &= \frac{ak}{bk} \end{align}
How to transform a rational function into a straight line (or viceversa)
https://math.stackexchange.com/questions/2221205/how-to-transform-a-rational-function-into-a-straight-line-or-viceversa
After some thinking, the answer seems obvious to me now: If we assume that \frac{a}{b}\in[0,1] no matter what value a takes, it is evident that the desired curve c\left(\frac{a}{b}\right), or ...
Is there a relationship for a triangle's side lengths, altitude/height, and acute/obtuse/right?
https://math.stackexchange.com/q/2451503
Don't need the height. Pythagoras (assuming c is the longest side): if c^2 = a^2 + b^2, then it is right; if c^2 < a^2 + b^2, then it is acute (or what you call acute non-right); if c^2 > a^2 + b^2 ...
exchange on sets with rank one
https://math.stackexchange.com/questions/2836768/exchange-on-sets-with-rank-one
Your argument works just fine, and algebraic closure does indeed define a pregeometry on sets of Morley rank 1. But this is not so surprising: sets of Morley rank 1 are not so far away from ...
More Items
Share
Copy
Copied to clipboard
3a=cb
Multiply both sides of the equation by b.
3a=bc
The equation is in standard form.
\frac{3a}{3}=\frac{bc}{3}
Divide both sides by 3.
a=\frac{bc}{3}
Dividing by 3 undoes the multiplication by 3.
3a=cb
Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by b.
cb=3a
Swap sides so that all variable terms are on the left hand side.
\frac{cb}{c}=\frac{3a}{c}
Divide both sides by c.
b=\frac{3a}{c}
Dividing by c undoes the multiplication by c.
b=\frac{3a}{c}\text{, }b\neq 0
Variable b cannot be equal to 0.
Similar Problems
3(r+2s)=2t-4
a \cdot (b-2) = 3b
b-y=-mx
\frac{3a}{b}=c
Back to top