Solve for a

a=\frac{bc}{3},b\neq 0

$a=3bc ,b=0$

Solve for b

\left\{\begin{matrix}b=\frac{3a}{c}\text{, }&a\neq 0\text{ and }c\neq 0\\b\neq 0\text{, }&c=0\text{ and }a=0\end{matrix}\right.

${b=c3a ,b=0, a=0andc=0c=0anda=0 $

Solve for c

c=\frac{3a}{b},b\neq 0

$c=b3a ,b=0$

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3a=cb

Multiply both sides of the equation by b.

3a=bc

The equation is in standard form.

\frac{3a}{3}=\frac{bc}{3}

Divide both sides by 3.

a=\frac{bc}{3}

Dividing by 3 undoes the multiplication by 3.

3a=cb

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by b.

cb=3a

Swap sides so that all variable terms are on the left hand side.

\frac{cb}{c}=\frac{3a}{c}

Divide both sides by c.

b=\frac{3a}{c}

Dividing by c undoes the multiplication by c.

b=\frac{3a}{c}\text{, }b\neq 0

Variable b cannot be equal to 0.

3a=cb

Multiply both sides of the equation by b.

cb=3a

Swap sides so that all variable terms are on the left hand side.

bc=3a

The equation is in standard form.

\frac{bc}{b}=\frac{3a}{b}

Divide both sides by b.

c=\frac{3a}{b}

Dividing by b undoes the multiplication by b.