Solve x^2-5x+3y=20

$$x ^ { 2 } - 5 x + 3 y = 20$$

Solve for y

$$y=\frac{20+5x-x^{2}}{3}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$-5x+3y=20-x^{2}$$

Add 5x to both sides.

$$3y=20-x^{2}+5x$$

The equation is in standard form.

$$3y=20+5x-x^{2}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{20+5x-x^{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{20+5x-x^{2}}{3}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{105-12y}+5}{2}$$

$$x=\frac{-\sqrt{105-12y}+5}{2}$$

Solve for x

$$x=\frac{\sqrt{105-12y}+5}{2}$$

$$x=\frac{-\sqrt{105-12y}+5}{2}\text{, }y\leq \frac{35}{4}$$