Factor

\left(x-4\right)\left(x^{2}+4x+16\right)

$(x−4)(x_{2}+4x+16)$

Evaluate

x^{3}-64

$x_{3}−64$

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\left(x-4\right)\left(x^{2}+4x+16\right)

Rewrite x^{3}-64 as x^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial x^{2}+4x+16 is not factored since it does not have any rational roots.