Type a math problem

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Type a math problem

Factor

\left(x-4\right)\left(x^{2}+4x+16\right)

$(x−4)(x_{2}+4x+16)$

Solution Steps

x^3-64

$x_{3}−64$

Rewrite x^{3}-64 as x^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial x^{2}+4x+16 is not factored since it does not have any rational roots.

Rewrite $x_{3}−64$ as $x_{3}−4_{3}$. The difference of cubes can be factored using the rule: $a_{3}−b_{3}=(a−b)(a_{2}+ab+b_{2})$. Polynomial $x_{2}+4x+16$ is not factored since it does not have any rational roots.

\left(x-4\right)\left(x^{2}+4x+16\right)

$(x−4)(x_{2}+4x+16)$

Evaluate

x^{3}-64

$x_{3}−64$

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\left(x-4\right)\left(x^{2}+4x+16\right)

Rewrite x^{3}-64 as x^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial x^{2}+4x+16 is not factored since it does not have any rational roots.

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