Type a math problem

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Type a math problem

Factor

\left(x+3\right)\left(x+8\right)

$(x+3)(x+8)$

Solution Steps

Steps Using the Quadratic Formula

Steps Using Direct Factoring Method

Solution Steps

x^2+11x+24

$x_{2}+11x+24$

Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+24. To find a and b, set up a system to be solved.

Factor the expression by grouping. First, the expression needs to be rewritten as $x_{2}+ax+bx+24$. To find $a$ and $b$, set up a system to be solved.

a+b=11 ab=1\times 24=24

$a+b=11$ $ab=1×24=24$

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.

Since $ab$ is positive, $a$ and $b$ have the same sign. Since $a+b$ is positive, $a$ and $b$ are both positive. List all such integer pairs that give product $24$.

1,24 2,12 3,8 4,6

$1,24$ $2,12$ $3,8$ $4,6$

Calculate the sum for each pair.

Calculate the sum for each pair.

1+24=25 2+12=14 3+8=11 4+6=10

$1+24=25$ $2+12=14$ $3+8=11$ $4+6=10$

The solution is the pair that gives sum 11.

The solution is the pair that gives sum $11$.

a=3 b=8

$a=3$ $b=8$

Rewrite x^{2}+11x+24 as \left(x^{2}+3x\right)+\left(8x+24\right).

Rewrite $x_{2}+11x+24$ as $(x_{2}+3x)+(8x+24)$.

\left(x^{2}+3x\right)+\left(8x+24\right)

$(x_{2}+3x)+(8x+24)$

Factor out x in the first and 8 in the second group.

Factor out $x$ in the first and $8$ in the second group.

x\left(x+3\right)+8\left(x+3\right)

$x(x+3)+8(x+3)$

Factor out common term x+3 by using distributive property.

Factor out common term $x+3$ by using distributive property.

\left(x+3\right)\left(x+8\right)

$(x+3)(x+8)$

Evaluate

\left(x+3\right)\left(x+8\right)

$(x+3)(x+8)$

Graph

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a+b=11 ab=1\times 24=24

Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+24. To find a and b, set up a system to be solved.

1,24 2,12 3,8 4,6

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 24.

1+24=25 2+12=14 3+8=11 4+6=10

Calculate the sum for each pair.

a=3 b=8

The solution is the pair that gives sum 11.

\left(x^{2}+3x\right)+\left(8x+24\right)

Rewrite x^{2}+11x+24 as \left(x^{2}+3x\right)+\left(8x+24\right).

x\left(x+3\right)+8\left(x+3\right)

Factor out x in the first and 8 in the second group.

\left(x+3\right)\left(x+8\right)

Factor out common term x+3 by using distributive property.

x^{2}+11x+24=0

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

x=\frac{-11±\sqrt{11^{2}-4\times 24}}{2}

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

x=\frac{-11±\sqrt{121-4\times 24}}{2}

Square 11.

x=\frac{-11±\sqrt{121-96}}{2}

Multiply -4 times 24.

x=\frac{-11±\sqrt{25}}{2}

Add 121 to -96.

x=\frac{-11±5}{2}

Take the square root of 25.

x=\frac{-6}{2}

Now solve the equation x=\frac{-11±5}{2} when ± is plus. Add -11 to 5.

x=-3

Divide -6 by 2.

x=\frac{-16}{2}

Now solve the equation x=\frac{-11±5}{2} when ± is minus. Subtract 5 from -11.

x=-8

Divide -16 by 2.

x^{2}+11x+24=\left(x-\left(-3\right)\right)\left(x-\left(-8\right)\right)

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -3 for x_{1} and -8 for x_{2}.

x^{2}+11x+24=\left(x+3\right)\left(x+8\right)

Simplify all the expressions of the form p-\left(-q\right) to p+q.

x ^ 2 +11x +24 = 0

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.

r + s = -11 rs = 24

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

r = -\frac{11}{2} - u s = -\frac{11}{2} + u

Two numbers r and s sum up to -11 exactly when the average of the two numbers is \frac{1}{2}*-11 = -\frac{11}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

(-\frac{11}{2} - u) (-\frac{11}{2} + u) = 24

To solve for unknown quantity u, substitute these in the product equation rs = 24

\frac{121}{4} - u^2 = 24

Simplify by expanding (a -b) (a + b) = a^2 – b^2

-u^2 = 24-\frac{121}{4} = -\frac{25}{4}

Simplify the expression by subtracting \frac{121}{4} on both sides

u^2 = \frac{25}{4} u = \pm\sqrt{\frac{25}{4}} = \pm \frac{5}{2}

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

r =-\frac{11}{2} - \frac{5}{2} = -8 s = -\frac{11}{2} + \frac{5}{2} = -3

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

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