求解 y=sqrt[3]{a+bx^5}

$$y = \sqrt[ 3 ] { a + b x ^ { 5 } }$$

求解 a 的值 (复数求解)

$$a=y^{3}-bx^{5}$$

$$arg(y)<\frac{2\pi }{3}\text{ or }y=0$$

求解 b 的值 (复数求解)

$$\left\{\begin{matrix}b=-\frac{a-y^{3}}{x^{5}}\text{, }&x\neq 0\text{ and }\left(arg(y)<\frac{2\pi }{3}\text{ or }y=0\right)\\b\in \mathrm{C}\text{, }&\left(a=0\text{ and }x=0\text{ and }y=0\right)\text{ or }\left(a=y^{3}\text{ and }x=0\text{ and }arg(y)<\frac{2\pi }{3}\text{ and }y\neq 0\right)\end{matrix}\right.$$

求解 a 的值

$$a=y^{3}-bx^{5}$$

求解 b 的值

$$\left\{\begin{matrix}b=-\frac{a-y^{3}}{x^{5}}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&y=\sqrt[3]{a}\text{ and }x=0\end{matrix}\right.$$