求解 x 的值
x=\pi +2n_{3}\pi +arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})\text{, }n_{3}\in \mathrm{Z}\text{, }\exists n_{42}\in \mathrm{Z}\text{ : }\left(n_{3}>\pi ^{-1}\left(\left(-\frac{1}{4}\right)\pi \right)+\pi ^{-1}\left(\left(-\frac{1}{2}\right)arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})\right)+\frac{1}{2}n_{42}\text{ and }n_{3}<\pi ^{-1}\times \left(\frac{1}{4}\pi \right)+\pi ^{-1}\left(\left(-\frac{1}{2}\right)arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})\right)+\frac{1}{2}n_{42}\right)
x=arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})+2\pi n_{22}\text{, }n_{22}\in \mathrm{Z}\text{, }\exists n_{42}\in \mathrm{Z}\text{ : }\left(n_{42}<\pi ^{-1}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})+\pi ^{-1}\left(\left(-\frac{1}{2}\right)\pi \right)+2n_{22}\text{ and }n_{42}>\pi ^{-1}arcSin(y\left(y^{2}+1\right)^{-\frac{1}{2}})+\pi ^{-1}\left(\left(-\frac{3}{2}\right)\pi \right)+2n_{22}\right)
求解 y 的值
y=\tan(x)
\nexists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}
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