求解 h(u)=(3u^2+5)^3(3u-1)^2 | Microsoft Math Solver

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\left(27\left(u^{2}\right)^{3}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

使用二项式定理 \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} 展开 \left(3u^{2}+5\right)^{3}。

\left(27u^{6}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

要对幂进行幂运算，即将指数相乘。2 乘 3 得 6。

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(3u-1\right)^{2}

要对幂进行幂运算，即将指数相乘。2 乘 2 得 4。

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(9u^{2}-6u+1\right)

使用二项式定理 \left(a-b\right)^{2}=a^{2}-2ab+b^{2} 展开 \left(3u-1\right)^{2}。

243u^{8}-162u^{7}+1242u^{6}-810u^{5}+2160u^{4}-1350u^{3}+1350u^{2}-750u+125

使用分配律将 27u^{6}+135u^{4}+225u^{2}+125 乘以 9u^{2}-6u+1，并组合同类项。