求解 {l}{A=690x/h^2}{a=x}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { A = \frac{690 x}{h ^ {2}} }\\ { a = x }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

求解 x 的值 (复数求解)

$$x=\frac{Ah^{2}}{690}$$

$$\left(h\neq 0\text{ and }a=0\text{ and }A=0\text{ and }b=0\right)\text{ or }\left(h=-A^{-\frac{1}{2}}\sqrt{690b}\text{ and }b\neq 0\text{ and }A\neq 0\text{ and }a=b\right)\text{ or }\left(h=A^{-\frac{1}{2}}\sqrt{690b}\text{ and }b\neq 0\text{ and }A\neq 0\text{ and }a=b\right)$$

求解 x 的值

$$x=\frac{Ah^{2}}{690}$$

$$\left(a=0\text{ and }A=0\text{ and }b=0\text{ and }h\neq 0\right)\text{ or }\left(h\neq 0\text{ and }a=b\text{ and }A<0\text{ and }b<0\text{ and }|h|=\sqrt{\frac{690b}{A}}\right)\text{ or }\left(h\neq 0\text{ and }a=b\text{ and }A>0\text{ and }b>0\text{ and }|h|=\sqrt{\frac{690b}{A}}\right)$$