求解 x_2 的值
\left\{\begin{matrix}x_{2}\in \begin{bmatrix}0,70-2x_{1}\end{bmatrix}\text{, }&x_{1}\geq 25\text{ and }x_{1}\leq 35\\x_{2}\in \begin{bmatrix}0,-\frac{4x_{1}}{5}+40\end{bmatrix}\text{, }&x_{1}\geq 0\text{ and }x_{1}<25\end{matrix}\right.
求解 x_1 的值
\left\{\begin{matrix}x_{1}\in \begin{bmatrix}0,-\frac{x_{2}}{2}+35\end{bmatrix}\text{, }&x_{2}\geq 0\text{ and }x_{2}\leq 20\\x_{1}\in \begin{bmatrix}0,-\frac{5x_{2}}{4}+50\end{bmatrix}\text{, }&x_{2}>20\text{ and }x_{2}\leq 40\end{matrix}\right.
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