求解 {l}{t_{1}=frac{ln(frac{x_{m}}{x_{0}}-1)-1.31}{r_{0}}}{t_{2}=frac{ln(frac{x_{m}}{x_{0}}-1)+(.31)}{r_{0}}}

$$\left\{ \begin{array} { l } { t _ { 1 } = \frac { \ln ( \frac { x _ { m } } { x _ { 0 } } - 1 ) - 1.31 } { r _ { 0 } } } \\ { t _ { 2 } = \frac { \ln ( \frac { x _ { m } } { x _ { 0 } } - 1 ) + ( .31 ) } { r _ { 0 } } } \end{array} \right.$$

求解 t_1, x_m, x_0, r_0, t_2 的值

$$t_{1}=\frac{\ln(\frac{x_{m}-x_{0}}{x_{0}})-1.31}{r_{0}}$$

$$x_{m}\in \mathrm{R}$$

$$x_{0}\in \mathrm{R}$$

$$r_{0}\in \mathrm{R}$$

$$t_{2}=\frac{\ln(\frac{x_{m}-x_{0}}{x_{0}})+0.31}{r_{0}}$$