求解 x-1/x^2+2y-2/x^2-2y=x/x^2-4

$$\frac{ x-1 }{ { x }^{ 2 } +2y } - \frac{ 2 }{ { x }^{ 2 } -2y } = \frac{ x }{ { x }^{ 2 } -4 }$$

求解 y 的值

$$\left\{\begin{matrix}y=\frac{-\sqrt{x^{6}+14x^{5}+9x^{4}-64x^{3}+8x^{2}+32x+16}+x^{3}+x^{2}-4x-4}{4x}\text{, }&x\neq 0\text{ and }x^{6}+14x^{5}+9x^{4}-64x^{3}+8x^{2}+32x\geq -16\text{ and }x^{6}+14x^{5}+9x^{4}-64x^{3}+8x^{2}+32x+16\geq 0\text{ and }|x|\neq 2\\y=\frac{\sqrt{x^{6}+14x^{5}+9x^{4}-64x^{3}+8x^{2}+32x+16}+x^{3}+x^{2}-4x-4}{4x}\text{, }&x\neq 1\text{ and }x\neq 0\text{ and }x^{6}+14x^{5}+9x^{4}-64x^{3}+8x^{2}+32x\geq -16\text{ and }x^{6}+14x^{5}+9x^{4}-64x^{3}+8x^{2}+32x+16\geq 0\text{ and }|x|\neq 2\end{matrix}\right.$$