Overslaan en naar de inhoud gaan
Microsoft
|
Math Solver
Oplossen
Spelen
Oefenen
Download
Oplossen
Oefenen
Spelen
Spel Centraal
Plezier + Vaardigheden verbeteren = winnen!
Onderwerpen
Pre-Algebra
Gemiddelde
Modus
Grootste Gemene Deler
Kleinste Gemene Veelvoud
Bewerkingsvolgorde
Breuken
Gemengde Breuken
Ontbinding in priemfactoren
Exponenten
Wortels
Algebra
Combineer Soortgelijke Termen
Een variabele oplossen
Factor
Uitbreiden
Breuken evalueren
Lineaire Vergelijkingen
Vierkantsvergelijkingen
Ongelijkheden
Stelsels van vergelijking
Matrices
Trigonometrie
Vereenvoudigen
Evalueren
Grafieken
Vergelijkingen oplossen
Analyse
Afgeleiden
Integralen
Limieten
Algebracalculator
Trigonometrische calculator
Calculuscalculator
Grafische Rekenmachine
Download
Spel Centraal
Plezier + Vaardigheden verbeteren = winnen!
Onderwerpen
Pre-Algebra
Gemiddelde
Modus
Grootste Gemene Deler
Kleinste Gemene Veelvoud
Bewerkingsvolgorde
Breuken
Gemengde Breuken
Ontbinding in priemfactoren
Exponenten
Wortels
Algebra
Combineer Soortgelijke Termen
Een variabele oplossen
Factor
Uitbreiden
Breuken evalueren
Lineaire Vergelijkingen
Vierkantsvergelijkingen
Ongelijkheden
Stelsels van vergelijking
Matrices
Trigonometrie
Vereenvoudigen
Evalueren
Grafieken
Vergelijkingen oplossen
Analyse
Afgeleiden
Integralen
Limieten
Algebracalculator
Trigonometrische calculator
Calculuscalculator
Grafische Rekenmachine
Oplossen
algebra
Trigonometrie
statistieken
analyse
matrices
variabelen
lijst
4%20%60frac%7B%2015%20%20%7D%7B%2032%20%20%7D%20
Evalueren
4
Factoriseren
2^{2}
Grafiek
Quiz
5 opgaven vergelijkbaar met:
4%20%60frac%7B%2015%20%20%7D%7B%2032%20%20%7D%20
Vergelijkbare problemen van Web Search
sum of all coprimes of a number.
https://math.stackexchange.com/questions/569210/sum-of-all-coprimes-of-a-number
Yes, the formula is right and if you reached it by yourself it is remarkable. If \;\phi(n)\; is Euler's Totient Function, then the sum you want is \frac n2\phi(n)=\frac{n^2}2\prod_{p\mid n\,,\,p\,\text{a prime}}\left(1-\frac1p\right) ...
How much money should we take?
https://math.stackexchange.com/questions/459602/how-much-money-should-we-take
Let f(n) be the expected final win for a player already having a balance of n and employing the optimal strategy. Trivially, f(n)\ge n as he might decide to stop right now. However, if the ...
P(A \cap B) = \frac14, P(\neg A) = \frac13, P(B) = \frac12, P(A \cup B) =?
https://math.stackexchange.com/questions/2003363/pa-cap-b-frac14-p-neg-a-frac13-pb-frac12-pa-cup-b
You correctly state that: P(A\cup B) = P(A)+P(B)-P(A\cap B) Then you try to calculate P(A\cap B) from P(A) and P(B) when (a) you do not know that they are independent and (b) you already ...
Calculating the fair price of an option knowing that selling the stock to the market carries a 2\% fee
https://math.stackexchange.com/questions/2268663/calculating-the-fair-price-of-an-option-knowing-that-selling-the-stock-to-the-ma
The solution for this would be Risk Neutral Probability = \frac{(1-d-(1+r)k)}{u-d-(1+r)k} Fair Price of the Option = \frac{1}{1+r}\left(p\psi{(u)}+(1-p)\psi{(d)}\right) where \psi{(u)} = Max((110-100),0) = 10 ...
Prove that \frac{1}{a(a-b)(a-c)} +\frac{1}{b(b-c)(b-a)} +\frac{1}{c(c-a)(c-b)} =\frac{1}{abc} for all sets of distinct nonzero numbers a,b,c.
https://math.stackexchange.com/questions/1579934/prove-that-frac1aa-ba-c-frac1bb-cb-a-frac1cc-ac-b
First, I'll mention an elementary way to finish the proof. Observe that this could be done by expanding the following product: f(c)=bc(b−c)−ac(a−c)+ab(a−b)−(a−b)(a−c)(b−c). At the end, you ...
What sort of particles corresponds to the (1,1/2) representation of the Lorentz group?
https://physics.stackexchange.com/q/439085
I think that my question wasn't actually well defined. For starters, when you restrict to the SO(3) subgroup of the (j_1, j_2) rep. of the Lorentz group, you get the j_1 \otimes j_2 rep of ...
Meer Items
Delen
Kopiëren
Gekopieerd naar klembord
Soortgelijke problemen
3 \frac{ 3 }{ 7 }
4 \frac{ 15 }{ 32 }
1 \frac{ 1 }{ 2 } +3 \frac{ 4 }{ 5 }
1 \frac{ 1 }{ 2 } -3 \frac{ 4 }{ 5 }
1 \frac{ 1 }{ 2 } \times 3 \frac{ 4 }{ 5 }
1 \frac{ 1 }{ 2 } \div 3 \frac{ 4 }{ 5 }
Terug naar boven