समाधान {l}{sin(θ)=1/sqrt{3}}{a=cos(2θ)}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { \sin(\theta) = \frac{1}{\sqrt{3}} }\\ { a = \cos(2 \theta) }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

θ, a, b को लागि हल गर्नुहोस्

$$\theta =2\pi n_{1}+\arcsin(\frac{\sqrt{3}}{3})\text{, }n_{1}\in \mathrm{Z}\text{, }a=\frac{1}{3}\approx 0.333333333\text{, }b=\frac{1}{3}\approx 0.333333333$$

$$\theta =2\pi n_{2}-\arcsin(\frac{\sqrt{3}}{3})+\pi \text{, }n_{2}\in \mathrm{Z}\text{, }a=\frac{1}{3}\approx 0.333333333\text{, }b=\frac{1}{3}\approx 0.333333333$$