समाधान d/dx{tan^-1sqrt{1-cosx/1+cosx}}=?

$$\frac { d } { d x } \{ \tan ^ { - 1 } \sqrt { \frac { 1 - \cos x } { 1 + \cos x } } \} = ?$$

मूल्याङ्कन गर्नुहोस्

$$\frac{\tan(\frac{x}{2})}{2|\tan(\frac{x}{2})|}$$

भिन्नता w.r.t. x

$$\frac{-\left(\frac{\cos(x)}{|\tan(\frac{x}{2})|\left(\cos(x)+1\right)}\right)^{3}-\frac{\left(\sin(x)\right)^{2}}{\left(|\tan(\frac{x}{2})|\left(\cos(x)+1\right)\right)^{3}}+\frac{\cos(x)}{\left(|\tan(\frac{x}{2})|\left(\cos(x)+1\right)\right)^{3}}+\frac{\left(\sin(x)\right)^{2}}{\sqrt{\left(-\cos(x)+1\right)\left(\cos(x)+1\right)^{3}}}}{2}$$