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12x
Ara l-passi tas-soluzzjoni
Passi għall-Użu ta' Definizzjoni ta' Dervattiv
\frac { d } { d x } ( 6 x ^ 2 )
Id-derivattiv ta' ax^{n} huwa nax^{n-1}.
2\times 6x^{2-1}
Immultiplika 2 b'6.
12x^{2-1}
Naqqas 1 minn 2.
12x^{1}
Għal kwalunkwe terminu t, t^{1}=t.
12x
Iddifferenzja w.r.t. x
12
Kwizz
Differentiation
\frac { d } { d x } ( 6 x ^ 2 )
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d/dx ((2x)^2) =d/dx (4x^2) =4 d/dx ( x^2) =4 * 2 * (x ^ (2-1)) =8x
How to get derivative of \frac{d}{dX}(X^TX) and \frac{d}{dX}(XX^T)
https://math.stackexchange.com/q/2714787
For matrix-valued functions I like to express derivatives in terms of the differential. If \delta X is a variation of X, then d\left[X^TX\right](\delta X) = \delta X^TX + X^T\delta X, where by ...
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The problem is that y is a function of x, that is y=y(x). Using the chain rule you can compute \begin{equation} \frac{d(y^2(x))}{dx} = 2y \frac{dy}{dx} \end{equation} You should read the chain ...
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I think you're being asked to know the following fact. Let f be any reasonably nice function — smooth is plenty good enough. Then \frac{\mathrm d}{\mathrm d x} \int_0^x f(t)\,\mathrm d t = f(x). ...
Extrapolating properties of rational numbers to irrational/transcendental numbers
https://math.stackexchange.com/questions/51369/extrapolating-properties-of-rational-numbers-to-irrational-transcendental-number
The type of argument you describe is a big motivation for the definition of a continuous function . A basic result which captures the spirit of what you want is this: a continuous function f : X \to Y ...
Derivative Notation Including Chain Rule
https://math.stackexchange.com/questions/1494555/derivative-notation-including-chain-rule/1494559
Let g(x)=x^3, then f(x^3)=f(g(x)). Then use the chain rule (f(g(x)))' = f'(g(x))g'(x) So we just need f'(x) and g'(x). f'(x) = 3x^2 and g'(x) = 3x^2 as well (because f and g ...
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Ikkupjat fuq il-klibbord
2\times 6x^{2-1}
Id-derivattiv ta' ax^{n} huwa nax^{n-1}.
12x^{2-1}
Immultiplika 2 b'6.
12x^{1}
Naqqas 1 minn 2.
12x
Għal kwalunkwe terminu t, t^{1}=t.
Problemi Simili
\frac { d } { d x } ( 2 )
\frac { d } { d x } ( 4 x )
\frac { d } { d x } ( 6 x ^ 2 )
\frac { d } { d x } ( 3x+7 )
\frac { d } { d a } ( 6a ( a -2) )
\frac { d } { d z } ( \frac{z+3}{2z-4} )
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