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4
Ara l-passi tas-soluzzjoni
Passi għall-Użu ta' Definizzjoni ta' Dervattiv
\frac { d } { d x } ( 4 x )
Id-derivattiv ta' ax^{n} huwa nax^{n-1}.
4x^{1-1}
Naqqas 1 minn 1.
4x^{0}
Għal kwalunkwe terminu t ħlief 0, t^{0}=1.
4\times 1
Għal kwalunkwe terminu t, t\times 1=t u 1t=t.
4
Iddifferenzja w.r.t. x
0
Kwizz
Differentiation
5 problemi simili għal:
\frac { d } { d x } ( 4 x )
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It does not a priori make sense to differentiate x! because the domain of x\mapsto x! is \mathbf N, not \mathbf R (or anything else supporting a good notion of differentiation, like \mathbf C ...
How to rewrite \frac{d}{d(x+c)}? [closed]
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https://math.stackexchange.com/questions/2894024/intuitive-explanation-of-frac-mathrmd-mathrmdx-0
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https://math.stackexchange.com/q/65332
Everything is correct, except that the derivative of a constant (like 6) is always 0. You can still see this fact from the power rule. Write 6 as 6x^0. The power rule says that the derivative is 6 \cdot 0 x^{-1} ...
How do I handle dx in u-substitution?
https://math.stackexchange.com/questions/927265/how-do-i-handle-dx-in-u-substitution
If you choose u=x^2+1, then taking the derivative with respect to x gives: \frac{\textrm{d}u}{\textrm{d}x}=2x. Therefore \textrm{d}u=2x\textrm{d}x or x\textrm{d}x=\textrm{d}u/2. Now your ...
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Sehem
Kopja
Ikkupjat fuq il-klibbord
4x^{1-1}
Id-derivattiv ta' ax^{n} huwa nax^{n-1}.
4x^{0}
Naqqas 1 minn 1.
4\times 1
Għal kwalunkwe terminu t ħlief 0, t^{0}=1.
4
Għal kwalunkwe terminu t, t\times 1=t u 1t=t.
Problemi Simili
\frac { d } { d x } ( 2 )
\frac { d } { d x } ( 4 x )
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\frac { d } { d a } ( 6a ( a -2) )
\frac { d } { d z } ( \frac{z+3}{2z-4} )
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