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4a^{2}
Bezakan w.r.t. a
8a
Kuiz
Algebra
\sqrt{\sqrt{256a^8}}
Masalah Sama dari Carian Web
4sqrt(256a^12b^20)
https://www.tiger-algebra.com/drill/4sqrt(256a~12b~20)/
sqrt(256a12b20) Simplified Root : 16 a6b10 Simplify : sqrt(256a12b20) Step 1 :Simplify the Integer part of the SQRT Factor 256 into its prime factors 256 = 28 To simplify a ...
sqrt(275t^8pq^7)
https://www.tiger-algebra.com/drill/sqrt(275t~8pq~7)/
sqrt(275t8pq7) Simplified Root : 5 t4q3 • sqrt(11pq) Simplify : sqrt(275t8pq7) Step 1 :Simplify the Integer part of the SQRT Factor 275 into its prime factors 275 = 52 • 11 ...
sqrt(24a^9b^14)
https://www.tiger-algebra.com/drill/sqrt(24a~9b~14)/
sqrt(24a9b14) Simplified Root : 2 a4b7 • sqrt(6a) Simplify : sqrt(24a9b14) Step 1 :Simplify the Integer part of the SQRT Factor 24 into its prime factors 24 = 23 • 3 To ...
How do you find the absolute maximum and absolute minimum values of f on the given interval: \displaystyle{f{{\left({t}\right)}}}={t}\sqrt{{{25}-{t}^{{2}}}} on [-1, 5]?
https://socratic.org/questions/how-do-you-find-the-absolute-maximum-and-absolute-minimum-values-of-f-on-the-giv-3
Reqd. extreme values are \displaystyle-\frac{{25}}{{2}}{\quad\text{and}\quad}\frac{{25}}{{2}} . Explanation: We use substitution \displaystyle{t}={5}{\sin{{x}}},{t}\in{\left[-{1},{5}\right]} ...
How do you simplify \displaystyle\sqrt{{{\left(-{21}\right)}^{{{2}}}+{\left({25}\right)}^{{{2}}}}} ?
https://socratic.org/questions/how-do-you-simplify-sqrt-21-2-25-2
See a solution process below: Explanation: Square and add the two terms in the radical: \displaystyle\sqrt{{{441}+{625}}}\Rightarrow\sqrt{{{1066}}}
How do you multiply \displaystyle{\left(\sqrt{{3}}+{2}\sqrt{{5}}\right)}^{{2}} ?
https://socratic.org/questions/how-do-you-multiply-sqrt3-2sqrt5-2
\displaystyle{\left(\sqrt{{{3}}}+{2}\sqrt{{{5}}}\right)}^{{2}} \displaystyle{\left(\text{XXXX}\right)} Explanation: \displaystyle{\left(\sqrt{{{3}}}+{2}\sqrt{{{5}}}\right)}^{{2}} \displaystyle{\left(\text{XXXX}\right)} ...
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Masalah yang serupa
\sqrt{40}
\sqrt{99a^3}
\sqrt{\frac{16}{25}}
\sqrt{3} \times \sqrt{3a^4}
\sqrt{\sqrt{256a^8}}
\sqrt{196}
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