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Nilaikan
3\sqrt{11}a^{\frac{3}{2}}
3
1
1
a
2
3
Bezakan w.r.t. a
\frac{9\sqrt{11a}}{2}
2
9
1
1
a
Kuiz
Algebra
5 masalah yang serupa dengan:
\sqrt{99a^3}
9
9
a
3
Masalah Sama dari Carian Web
How do you simplify \displaystyle\sqrt{{{49}{a}^{{8}}}} ?
How do you simplify
4
9
a
8
?
https://socratic.org/questions/how-do-you-simplify-sqrt-49-a-8
Alan P. Apr 7, 2015 \displaystyle\sqrt{{{49}{a}^{{8}}}}=\sqrt{{{7}^{{2}}\cdot{\left({a}^{{4}}\right)}^{{2}}}} \displaystyle={7}{a}^{{4}}
Alan P. Apr 7, 2015
4
9
a
8
=
7
2
⋅
(
a
4
)
2
=
7
a
4
How do you simplify \displaystyle\sqrt{{{9}{a}{b}^{{4}}}} ?
How do you simplify
9
a
b
4
?
https://socratic.org/questions/how-do-you-simplify-sqrt-9ab-4
\displaystyle={3}\cdot{b}^{{2}}\sqrt{{a}} Explanation: \displaystyle\sqrt{{{9}{a}{b}^{{4}}}} \displaystyle=\sqrt{{{3}\cdot{3}\cdot{a}\cdot{b}\cdot{b}\cdot{b}\cdot{b}}} \displaystyle=\sqrt{{{3}^{{2}}\cdot{a}\cdot{b}^{{2}}\cdot{b}^{{2}}}} ...
=
3
⋅
b
2
a
Explanation:
9
a
b
4
=
3
⋅
3
⋅
a
⋅
b
⋅
b
⋅
b
⋅
b
=
3
2
⋅
a
⋅
b
2
⋅
b
2
...
How do you simplify \displaystyle{4}{\sqrt[{3}]{{{a}^{{3}}}}} ?
How do you simplify
4
3
a
3
?
https://socratic.org/questions/how-do-you-simplify-4root3-a-3
\displaystyle{4}{\sqrt[{{3}}]{{{a}^{{3}}}}}={4}{a} Explanation: \displaystyle{4}{\sqrt[{{3}}]{{{a}^{{3}}}}} = \displaystyle{4}{\sqrt[{{3}}]{{{a}\times{a}\times{a}}}} = \displaystyle{4}{\sqrt[{{3}}]{\underline{{{\left({a}\times{a}\times{a}\right)}}}}} ...
4
3
a
3
=
4
a
Explanation:
4
3
a
3
=
4
3
a
×
a
×
a
=
4
3
(
a
×
a
×
a
)
...
What's the easiest way to make \frac{\sqrt{5a} \sqrt{10a^5}}{\sqrt{2 a}} into 5a^2 \sqrt{a}?
What's the easiest way to make
2
a
5
a
1
0
a
5
into
5
a
2
a
?
https://www.quora.com/Whats-the-easiest-way-to-make-frac-sqrt-5a-sqrt-10a-5-sqrt-2-a-into-5a-2-sqrt-a
Thank you for showing your work, so that we know we are not doing your homework for you. Let’s look at your fraction: \frac{\sqrt{5a}\cdot\sqrt{10a^5}}{\sqrt{2a}} Do you remember that \sqrt{AB} ...
Thank you for showing your work, so that we know we are not doing your homework for you. Let’s look at your fraction:
2
a
5
a
⋅
1
0
a
5
Do you remember that
A
B
...
How do you simplify \displaystyle\sqrt{{{49}{a}^{{{15}}}}} ?
How do you simplify
4
9
a
1
5
?
https://socratic.org/questions/how-do-you-simplify-sqrt-49a-15
\displaystyle{7}{a}^{{7.5}} Explanation: As \displaystyle{49}={7}\cdot{7}={7}^{{2}} , \displaystyle\sqrt{{49}}={7} And \displaystyle\sqrt{{{a}^{{15}}}}=\sqrt{{{a}^{{14}}}}\cdot\sqrt{{a}}={a}^{{7}}\sqrt{{a}}={a}^{{7.5}} ...
7
a
7
.
5
Explanation: As
4
9
=
7
⋅
7
=
7
2
,
4
9
=
7
And
a
1
5
=
a
1
4
⋅
a
=
a
7
a
=
a
7
.
5
...
sqrt(18a^3)
s
q
r
t
(
1
8
a
3
)
https://www.tiger-algebra.com/drill/sqrt(18a~3)/
sqrt(18a3) Simplified Root : 3 a • sqrt(2a) Simplify : sqrt(18a3) Step 1 :Simplify the Integer part of the SQRT Factor 18 into its prime factors 18 = 2 • 32 To simplify a ...
sqrt(18a3) Simplified Root : 3 a • sqrt(2a) Simplify : sqrt(18a3) Step 1 :Simplify the Integer part of the SQRT Factor 18 into its prime factors 18 = 2 • 32 To simplify a ...
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