Skip ໄປຫາເນື້ອຫາຫຼັກ
Microsoft
|
Math Solver
ແກ້
ການປະຕິບັດ
ຫຼິ້ນ
ຫົວຂໍ້
Pre-Algebra
Mean
Mode
ປັດໄຈທົ່ວໄປທີ່ຍິ່ງໃຫຍ່ທີ່ສຸດ
ຫນ້ອຍທີ່ສຸດທົ່ວໄປຫຼາຍ
ລະບຽບການດໍາເນີນງານ
ສ່ວນຍ່ອຍ
ສ່ວນປະກອບປະສົມ
ປັດຈຸບັນ
Exponents
Radicals
Algebra
Combine Like Terms
ແກ້ໄຂສໍາລັບVariable
ປັດໃຈ
ຂະຫຍາຍ
ປະເມີນຜົນສ່ວນປະກອບ
ສະສົມLinear Equations
ສະສົມQuadratic
ຄວາມບໍ່ສະເຫມີພາບ
ລະບົບຂອງEquations
ມັດທຣີສ
Trigonometry
ລຽບງ່າຍ
ປະເມີນຜົນ
Graphs
ແກ້ໄຂສະສົມ
Calculus
ຜະລິດຕະພັນ
Integrals
ຂີດຈໍາກັດ
Algebra Inputs
Trigonometry Inputs
Calculus Inputs
Matrix Inputs
ແກ້
ການປະຕິບັດ
ຫຼິ້ນ
ຫົວຂໍ້
Pre-Algebra
Mean
Mode
ປັດໄຈທົ່ວໄປທີ່ຍິ່ງໃຫຍ່ທີ່ສຸດ
ຫນ້ອຍທີ່ສຸດທົ່ວໄປຫຼາຍ
ລະບຽບການດໍາເນີນງານ
ສ່ວນຍ່ອຍ
ສ່ວນປະກອບປະສົມ
ປັດຈຸບັນ
Exponents
Radicals
Algebra
Combine Like Terms
ແກ້ໄຂສໍາລັບVariable
ປັດໃຈ
ຂະຫຍາຍ
ປະເມີນຜົນສ່ວນປະກອບ
ສະສົມLinear Equations
ສະສົມQuadratic
ຄວາມບໍ່ສະເຫມີພາບ
ລະບົບຂອງEquations
ມັດທຣີສ
Trigonometry
ລຽບງ່າຍ
ປະເມີນຜົນ
Graphs
ແກ້ໄຂສະສົມ
Calculus
ຜະລິດຕະພັນ
Integrals
ຂີດຈໍາກັດ
Algebra Inputs
Trigonometry Inputs
Calculus Inputs
Matrix Inputs
ພື້ນຖານ
algebra
trigonometry
calculus
ສະຖິຕິ
matrices
ຕົວອັກສອນ
ປະເມີນ
0
ບອກຄວາມແຕກຕ່າງ w.r.t. x
0
Quiz
Differentiation
\frac { d } { d x } ( 2 )
ບັນຫາທີ່ຄ້າຍຄືກັນຈາກWeb Search
let f be a differentiable function. Compute \frac{d}{dx}g(2), where g(x) = \frac{f(2x)}{x}.
https://math.stackexchange.com/questions/2351494/let-f-be-a-differentiable-function-compute-fracddxg2-where-gx
You have an extra 4 in the numerator here: i know that : \dfrac{d}{dx}g(2)=\dfrac{4(\dfrac{d}{dx}f(4))-4f(4)}{4} If g(x) = \dfrac{f(2x)}x, then \begin{align*} \frac d{dx} g(x) &= \frac d{dx} ...
How to rewrite \frac{d}{d(x+c)}? [closed]
https://math.stackexchange.com/questions/1376627/how-to-rewrite-fracddxc
Use the chain rule. Define u = x + c then use the fact that \frac{d\cdot}{dx} = \frac{du}{dx} \frac{d\cdot}{du} where the \cdot represents any function, so \frac{df}{dx} = \frac{du}{dx} \frac{df}{du} ...
What does is the meaning of \frac{d}{dx}+x in (\frac{d}{dx}+x)y=0?
https://math.stackexchange.com/q/1590756
The symbols d/dx and x should both be interpreted as linear operators acting on a vector space that the unknown function y belongs to. The sum of linear operators is well-defined and that is ...
Intuitive explanation of \frac{\mathrm{d}}{\mathrm{d}x}=0?
https://math.stackexchange.com/questions/2894024/intuitive-explanation-of-frac-mathrmd-mathrmdx-0
Not sure about the problem but the strength of the electrical field, E, depends on your distance from it, which I assume is x. \frac{dE}{dx} then, is how much the strength of the field changes ...
Question about the chain rule.
https://math.stackexchange.com/q/2940216
Suppose we add an infinitesimal to x : x_1=x_0+\Delta x . What happens to y ? By definition, the derivative tells us how much a function changes relative to changes in its input: the change ...
Spectrum of the derivative operator
https://math.stackexchange.com/questions/2117107/spectrum-of-the-derivative-operator
\newcommand{\id}{I} As it was mentioned in the comments, the domain where you defined the operator is not correct - If you take C^1-functions with derivatives in L^2 the domain will be "too ...
ລາຍການ
ແບ່ງປັນ
ສໍາເນົາ
ສໍາເນົາຄລິບ
ບັນຫາທີ່ຄ້າຍຄືກັນ
\frac { d } { d x } ( 2 )
\frac { d } { d x } ( 4 x )
\frac { d } { d x } ( 6 x ^ 2 )
\frac { d } { d x } ( 3x+7 )
\frac { d } { d a } ( 6a ( a -2) )
\frac { d } { d z } ( \frac{z+3}{2z-4} )
ກັບຄືນສູ່ຍອດ
