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Pre-Algebra
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ປັດໄຈທົ່ວໄປທີ່ຍິ່ງໃຫຍ່ທີ່ສຸດ
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ແກ້ສຳລັບ x
x\in \left(-\frac{4}{3},2\right)
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Algebra
5 ບັນຫາທີ່ຄ້າຍຄືກັນກັບ:
-2 < 3x+2 < 8
ບັນຫາທີ່ຄ້າຍຄືກັນຈາກWeb Search
How do you solve \displaystyle{2}={3}{x}+{3}{\left({2}{x}-{6}\right)} ?
https://socratic.org/questions/how-do-you-solve-2-3x-3-2x-6
\displaystyle{x}=\frac{{20}}{{9}} Explanation: First expand the parentheses: \displaystyle{2}={3}{x}+{3}{\left({2}{x}-{6}\right)} \displaystyle{2}={3}{x}+{\left({3}\cdot{2}{x}\right)}+{\left({3}\cdot-{6}\right)} ...
How do you solve \displaystyle-{2}{<}{3}{x}+{1}{<}{7} ?
https://socratic.org/questions/how-do-you-solve-2-3x-1-7
\displaystyle-{1}{<}{x}{<}{2} or the interval \displaystyle{\left(-{1},{2}\right)} Explanation: We start by subtracting 1 on each part of the equation: \displaystyle-{3}{<}{3}{x}{<}{6} ...
How do you solve \displaystyle{2}{\left({3}{x}+{4}\right)}-{3}={5}+{6}{x} ?
https://socratic.org/questions/how-do-you-solve-2-3x-4-3-5-6x
\displaystyle{x} can have have value. Explanation: Multiply out he bracket first \displaystyle{2}{\left({3}{x}+{4}\right)}-{3}={5}+{6}{x} \displaystyle{6}{x}+{8}-{3}={5}+{6}{x} \displaystyle{6}{x}+{5}={6}{x}+{5}\ \text{ }\ \leftarrow ...
How do you solve \displaystyle-{2}{<}{x}+{2}{<}{5} ?
https://socratic.org/questions/how-do-you-solve-2-x-2-5
See a solution process below Explanation: \displaystyle-{2}{<}{x}+{2}{<}{5} Cross \displaystyle{2} to the right hand side.. \displaystyle-{2}{<}{x}{<}{5}-{2} \displaystyle-{2}{<}{x}{<}{3} ...
How do you solve \displaystyle{2}{\left({4}-{x}\right)}+{8}{<}{15} ?
https://socratic.org/questions/how-do-you-solve-2-4-x-8-15
\displaystyle\frac{{1}}{{2}}{<}{x} Explanation: expand the bracket \displaystyle{8}-{2}{x}+{8}{<}{15} add \displaystyle{2}{x} \displaystyle{16}{<}{15}+{2}{x} subtract 15 \displaystyle{1}{<}{2}{x} ...
How do you solve \displaystyle-{6}{<}{3}{x}+{2}{<}{11} ?
https://socratic.org/questions/how-do-you-solve-6-3x-2-11
\displaystyle-\frac{{8}}{{3}}{<}{x}{<}{3} Explanation: Inequalities act just as equations do, for the most part. I'll show you what I mean: \displaystyle-{6}{<}{3}{x}+{2}{<}{11} Is the ...
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3x+4>6
x+y<0
5 > 2x + 3
-2 < 3x+2 < 8
2x^2 \geq 50
\frac{5}{3x+3} \leq 8
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