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Daftar
Atasi untuk x
x\in (-\infty,-5]\cup [5,\infty)
x
∈
(
−
∞
,
−
5
]
∪
[
5
,
∞
)
Lihat langkah-langkah penyelesaian
Langkah Solusi
2x^2 \geq 50
2
x
2
≥
5
0
Bagi kedua sisi dengan 2. Karena 2 adalah >0, arah pertidaksamaan tetap sama.
Bagi kedua sisi dengan
2
. Karena
2
adalah
>
0
, arah pertidaksamaan tetap sama.
x^{2}\geq \frac{50}{2}
x
2
≥
2
5
0
Bagi 50 dengan 2 untuk mendapatkan 25.
Bagi
5
0
dengan
2
untuk mendapatkan
2
5
.
x^{2}\geq 25
x
2
≥
2
5
Hitung akar kuadrat dari 25 dan dapatkan 5. Tulis ulang 25 sebagai 5^{2}.
Hitung akar kuadrat dari
2
5
dan dapatkan
5
. Tulis ulang
2
5
sebagai
5
2
.
x^{2}\geq 5^{2}
x
2
≥
5
2
Pertidaksamaan berlaku untuk |x|\geq 5.
Pertidaksamaan berlaku untuk
∣
x
∣
≥
5
.
|x|\geq 5
∣
x
∣
≥
5
Tulis ulang |x|\geq 5 sebagai x\leq -5\text{; }x\geq 5.
Tulis ulang
∣
x
∣
≥
5
sebagai
x
≤
−
5
;
x
≥
5
.
x\leq -5\text{; }x\geq 5
x
≤
−
5
;
x
≥
5
Grafik
Pertidaksamaan Grafik
Kedua Sisi Grafik dalam 2D
Kuis
Algebra
5 soal serupa dengan:
2x^2 \geq 50
2
x
2
≥
5
0
Soal yang Mirip dari Pencarian Web
If \displaystyle{4}-{x}^{{2}}\ge{0} isn't \displaystyle{x}\le\pm{2} ? I don't understand how \displaystyle-{2}\le{x}\le{2} is a result.
If
4
−
x
2
≥
0
isn't
x
≤
±
2
? I don't understand how
−
2
≤
x
≤
2
is a result.
https://socratic.org/questions/if-4-x-2-0-isn-t-x-2-i-don-t-understand-how-2-x-2-is-a-result
Please see below. Explanation: As \displaystyle{4}-{x}^{{2}}\ge{0} , we have \displaystyle{\left({2}-{x}\right)}{\left({2}+{x}\right)}\ge{0} This means product of \displaystyle{\left({2}-{x}\right)} ...
Please see below. Explanation: As
4
−
x
2
≥
0
, we have
(
2
−
x
)
(
2
+
x
)
≥
0
This means product of
(
2
−
x
)
...
How do I solve |-2x^2+1+e^x+\sin x| = |2x^2-1|+e^x+|\sin x| where x belongs to [0,2π]?
How do I solve
∣
−
2
x
2
+
1
+
e
x
+
sin
x
∣
=
∣
2
x
2
−
1
∣
+
e
x
+
∣
sin
x
∣
where x belongs to [0,2π]?
https://math.stackexchange.com/questions/3104697/how-do-i-solve-2x21ex-sin-x-2x2-1ex-sin-x-where-x-belongs-to
We have |a+b+c|=|a|+|b|+|c|\quad\hbox{if and only if}\quad \hbox{a,b,c all have the same sign}\ , where "same sign" is in the non-strict sense, that is, all {}\ge0 or all {}\le0 . In ...
We have where "same sign" is in the non-strict sense, that is, all
≥
0
or all
≤
0
. In ...
Which pairs of positive integers (푥,푛) satisfy 푥^2−2^푛=153?
Which pairs of positive integers (푥,푛) satisfy
푥
2
−
2
푛
=
1
5
3
?
https://math.stackexchange.com/questions/2919551/which-pairs-of-positive-integers-satisfy-2%e2%88%922-153
n must be even. 153 = 3^2 \cdot 17 If x^2 - 2 y^2 is divisible by 3, then both x,y are divisible by 3. Since this y would be a power of 2 this is impossible. So n is ...
n
must be even.
1
5
3
=
3
2
⋅
1
7
If
x
2
−
2
y
2
is divisible by
3
,
then both
x
,
y
are divisible by
3
.
Since this
y
would be a power of
2
this is impossible. So
n
is ...
Domain of {(x,y) | y = \sqrt{x^2 - 4}}
Domain of
(
x
,
y
)
∣
y
=
x
2
−
4
https://math.stackexchange.com/q/1423826
If x^2\ge a then |x|\ge \sqrt{a}. Not x\ge \sqrt{a}. Similarly, if x^2=a, |x|=\sqrt{a}. Not x=\sqrt{a}.
If
x
2
≥
a
then
∣
x
∣
≥
a
. Not
x
≥
a
. Similarly, if
x
2
=
a
,
∣
x
∣
=
a
. Not
x
=
a
.
Upper bound for a ratio of two least common multiples
Upper bound for a ratio of two least common multiples
https://math.stackexchange.com/questions/3026176/upper-bound-for-a-ratio-of-two-least-common-multiples
HINT 1 Note that r(x)={\large \dfrac {\mathrm{lcm}(x^2+x)}{\mathrm{lcm}(x^2)}\cdot{\dfrac {(x^2)\#}{(x^2+x)\#}} = \prod_{p_k<x+1} p_k^{[\log_{p_k}(x^2+x)]-[\log_{p_k}(x^2)]}}. Calculations ...
HINT
1
Note that
r
(
x
)
=
l
c
m
(
x
2
)
l
c
m
(
x
2
+
x
)
⋅
(
x
2
+
x
)
#
(
x
2
)
#
=
∏
p
k
<
x
+
1
p
k
[
l
o
g
p
k
(
x
2
+
x
)
]
−
[
l
o
g
p
k
(
x
2
)
]
.
Calculations ...
Calculate \int^1_{-1}\sqrt{(1-x^2)^3} dx using Integration by parts or substitution technique
Calculate
∫
−
1
1
(
1
−
x
2
)
3
d
x
using Integration by parts or substitution technique
https://math.stackexchange.com/questions/2216301/calculate-int1-1-sqrt1-x23-dx-using-integration-by-parts-or-substit
"1-x^2" should immediately make you think about the substitution x=\sin u, as 1-x^2 = 1-\sin^2 u = \cos^2 u. So let x = \sin u, then dx = \cos u \,du and note that \sin (-\tfrac{\pi}{2}) = -1 ...
"
1
−
x
2
" should immediately make you think about the substitution
x
=
sin
u
, as
1
−
x
2
=
1
−
sin
2
u
=
cos
2
u
. So let
x
=
sin
u
, then
d
x
=
cos
u
d
u
and note that
sin
(
−
2
π
)
=
−
1
...
Lebih banyak Item
Bagikan
Salin
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x^{2}\geq \frac{50}{2}
Bagi kedua sisi dengan 2. Karena 2 adalah >0, arah pertidaksamaan tetap sama.
x^{2}\geq 25
Bagi 50 dengan 2 untuk mendapatkan 25.
x^{2}\geq 5^{2}
Hitung akar kuadrat dari 25 dan dapatkan 5. Tulis ulang 25 sebagai 5^{2}.
|x|\geq 5
Pertidaksamaan berlaku untuk |x|\geq 5.
x\leq -5\text{; }x\geq 5
Tulis ulang |x|\geq 5 sebagai x\leq -5\text{; }x\geq 5.
Masalah Serupa
3x+4>6
3
x
+
4
>
6
x+y<0
x
+
y
<
0
5 > 2x + 3
5
>
2
x
+
3
-2 < 3x+2 < 8
−
2
<
3
x
+
2
<
8
2x^2 \geq 50
2
x
2
≥
5
0
\frac{5}{3x+3} \leq 8
3
x
+
3
5
≤
8
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