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Atasi untuk x
x<1
x
<
1
Lihat langkah-langkah penyelesaian
Langkah Solusi
5 > 2x + 3
5
>
2
x
+
3
Tukarkan sisi sehingga semua suku variabel ada di sisi kiri. Hal ini mengubah arah tanda.
Tukarkan sisi sehingga semua suku variabel ada di sisi kiri. Hal ini mengubah arah tanda.
2x+3<5
2
x
+
3
<
5
Kurangi 3 dari kedua sisi.
Kurangi
3
dari kedua sisi.
2x<5-3
2
x
<
5
−
3
Kurangi 3 dari 5 untuk mendapatkan 2.
Kurangi
3
dari
5
untuk mendapatkan
2
.
2x<2
2
x
<
2
Bagi kedua sisi dengan 2. Karena 2 adalah >0, arah pertidaksamaan tetap sama.
Bagi kedua sisi dengan
2
. Karena
2
adalah
>
0
, arah pertidaksamaan tetap sama.
x<\frac{2}{2}
x
<
2
2
Bagi 2 dengan 2 untuk mendapatkan 1.
Bagi
2
dengan
2
untuk mendapatkan
1
.
x<1
x
<
1
Grafik
Pertidaksamaan Grafik
Kedua Sisi Grafik dalam 2D
Kuis
Algebra
5 soal serupa dengan:
5 > 2x + 3
5
>
2
x
+
3
Soal yang Mirip dari Pencarian Web
.What is \displaystyle{x} if the sequence \displaystyle{1},{5},{2}{x}+{3} ....is an arithmetic sequence?
.What is
x
if the sequence
1
,
5
,
2
x
+
3
....is an arithmetic sequence?
https://socratic.org/questions/what-is-x-if-the-sequence-1-5-2x-3-is-an-arithmetic-sequence
\displaystyle{x}={3} Explanation: If the sequence is arithmeic, then there is common difference between the consecutive terms. \displaystyle{d}={T}_{{3}}-{T}_{{2}}={T}_{{2}}-{T}_{{1}} \displaystyle{\left({2}{x}+{3}\right)}-{5}={5}-{1}\ \text{ we have an equation - solve it} ...
x
=
3
Explanation: If the sequence is arithmeic, then there is common difference between the consecutive terms.
d
=
T
3
−
T
2
=
T
2
−
T
1
(
2
x
+
3
)
−
5
=
5
−
1
we have an equation - solve it
...
How do you graph \displaystyle{2}{x}+{8}={0} ?
How do you graph
2
x
+
8
=
0
?
https://socratic.org/questions/how-do-you-graph-2x-8-0
Solving the equation Explanation: Arrange the equation: \displaystyle{2}{x}=-{8} \displaystyle{x}=-\frac{{8}}{{2}} \displaystyle{x}=-{4} No matter what y is, your x is -4. It is a ...
Solving the equation Explanation: Arrange the equation:
2
x
=
−
8
x
=
−
2
8
x
=
−
4
No matter what y is, your x is -4. It is a ...
How do you graph the inequality \displaystyle{x}+{5}{>}{2}{x}+{1} and \displaystyle-{4}{x}{<}-{8} ?
How do you graph the inequality
x
+
5
>
2
x
+
1
and
−
4
x
<
−
8
?
https://socratic.org/questions/how-do-you-graph-the-inequality-x-5-2x-1-and-4x-8
The segment of the x-axis, in between x = 2 and x = 4. Explanation: From the first, x < 4. From the second, #-x<-2, and so, x > 2. The combined inequality is 2 < x < 4 and the graph for this is the ...
The segment of the x-axis, in between x = 2 and x = 4. Explanation: From the first, x < 4. From the second, #-x<-2, and so, x > 2. The combined inequality is 2 < x < 4 and the graph for this is the ...
How do you find the LCD for \displaystyle{2}{x},{3},{x}+{3} ?
How do you find the LCD for
2
x
,
3
,
x
+
3
?
https://socratic.org/questions/how-do-you-find-the-lcd-for-2x-3-x-3
The LCD is \displaystyle{\left({2}{x}\right)}{\left({3}\right)}{\left({x}+{3}\right)} Explanation: Since these 3 terms has no common factor; therefore, the same numbers will be the LCD of this ...
The LCD is
(
2
x
)
(
3
)
(
x
+
3
)
Explanation: Since these 3 terms has no common factor; therefore, the same numbers will be the LCD of this ...
How do you solve and graph the compound inequality \displaystyle{5}{>}-{2}{x}+{4} or \displaystyle{10}\le-{4}{x}+{3} ?
How do you solve and graph the compound inequality
5
>
−
2
x
+
4
or
1
0
≤
−
4
x
+
3
?
https://socratic.org/questions/how-do-you-solve-and-graph-the-compound-inequality-5-2x-4-or-10-4x-3
Nghi N. May 13, 2015 5 > -2x + 4 (1) -> 2x > -1 -> x > -1/2 10 <= -4x + 3 (2) -> 4x <= -7 -> x < -7/4 ===========|-7/4--------------|-1/2===|0=======
Nghi N. May 13, 2015 5 > -2x + 4 (1) -> 2x > -1 -> x > -1/2 10 <= -4x + 3 (2) -> 4x <= -7 -> x < -7/4 ===========|-7/4--------------|-1/2===|0=======
5(2+x+3)
5
(
2
+
x
+
3
)
https://www.tiger-algebra.com/drill/5(2_x_3)/
5(2+x+3) Final result : 5 • (x + 5) Step by step solution : Step 1 :Final result : 5 • (x + 5) Processing ends successfully
5(2+x+3) Final result : 5 • (x + 5) Step by step solution : Step 1 :Final result : 5 • (x + 5) Processing ends successfully
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2x+3<5
Tukarkan sisi sehingga semua suku variabel ada di sisi kiri. Hal ini mengubah arah tanda.
2x<5-3
Kurangi 3 dari kedua sisi.
2x<2
Kurangi 3 dari 5 untuk mendapatkan 2.
x<\frac{2}{2}
Bagi kedua sisi dengan 2. Karena 2 adalah >0, arah pertidaksamaan tetap sama.
x<1
Bagi 2 dengan 2 untuk mendapatkan 1.
Masalah Serupa
3x+4>6
3
x
+
4
>
6
x+y<0
x
+
y
<
0
5 > 2x + 3
5
>
2
x
+
3
-2 < 3x+2 < 8
−
2
<
3
x
+
2
<
8
2x^2 \geq 50
2
x
2
≥
5
0
\frac{5}{3x+3} \leq 8
3
x
+
3
5
≤
8
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