V_{3}=152m/segquadv_{4}=210m/seg megoldása

$$V _ { 3 } = 152 m / seg \quad v _ { 4 } = 210 m / seg$$

Kiértékelés (complex solution)

$$V_{3}=\frac{152egmv_{4}}{s}\text{ and }\frac{152egmv_{4}}{s}=\frac{210egm}{s}$$

Megoldás a(z) v_4 változóra

$$\left\{\begin{matrix}v_{4}=\frac{V_{3}s}{152egm}\text{, }&V_{3}=\frac{210egm}{s}\text{ and }g\neq 0\text{ and }s\neq 0\text{ and }m\neq 0\\v_{4}\in \mathrm{R}\text{, }&\left(g=0\text{ or }m=0\right)\text{ and }V_{3}=0\text{ and }s\neq 0\end{matrix}\right,$$

Megoldás a(z) s változóra

$$\left\{\begin{matrix}s=\frac{210egm}{V_{3}}\text{, }&v_{4}=\frac{105}{76}\text{ and }g\neq 0\text{ and }m\neq 0\text{ and }V_{3}\neq 0\\s\neq 0\text{, }&\left(m=0\text{ or }g=0\right)\text{ and }V_{3}=0\end{matrix}\right,$$