פתור את {l}{z=1+j}{a=z^19}{text{Solvefor}btext{where}}{b=a}

פתור עבור z, j, a, b (complex solution)

z=j+1\text{, }j=e^{\frac{36\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{34\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{32\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{30\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=-\left(e^{\frac{9\pi i}{19}}\sqrt[19]{b}+1\right)\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=-\left(e^{\frac{7\pi i}{19}}\sqrt[19]{b}+1\right)\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=-\left(e^{\frac{5\pi i}{19}}\sqrt[19]{b}+1\right)\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=-\left(e^{\frac{3\pi i}{19}}\sqrt[19]{b}+1\right)\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=-\left(e^{\frac{\pi i}{19}}\sqrt[19]{b}+1\right)\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{18\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{16\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{14\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{12\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{10\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{8\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{6\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{4\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=e^{\frac{2\pi i}{19}}\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

z=j+1\text{, }j=\sqrt[19]{b}-1\text{, }a=b\text{, }b\in \mathrm{C}

פתור עבור z, j, a, b

b=\left(j+1\right)^{19}

בוחן

Algebra

5 בעיות דומות ל:

\left. \begin{array} { l } { z = 1 + j }\\ { a = z ^ {19} }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.

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