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\frac{1+\left(1+2\right)^{2}}{6+7-5}
Subtract 3 from 4 to get 1.
\frac{1+3^{2}}{6+7-5}
Add 1 and 2 to get 3.
\frac{1+9}{6+7-5}
Calculate 3 to the power of 2 and get 9.
\frac{10}{6+7-5}
Add 1 and 9 to get 10.
\frac{10}{13-5}
Add 6 and 7 to get 13.
\frac{10}{8}
Subtract 5 from 13 to get 8.
\frac{5}{4}
Reduce the fraction \frac{10}{8} to lowest terms by extracting and canceling out 2.