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Topics
Pre-Algebra
Mean
Mode
Greatest Common Factor
Least Common Multiple
Order of Operations
Fractions
Mixed Fractions
Prime Factorization
Exponents
Radicals
Algebra
Combine Like Terms
Solve for a Variable
Factor
Expand
Evaluate Fractions
Linear Equations
Quadratic Equations
Inequalities
Systems of Equations
Matrices
Trigonometry
Simplify
Evaluate
Graphs
Solve Equations
Calculus
Derivatives
Integrals
Limits
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mode(2,4,5,3,2,4,5,6,4,3,2)
$mode(2,4,5,3,2,4,5,6,4,3,2)$
Evaluate
2,4
$2,4$
Quiz
5 problems similar to:
mode(2,4,5,3,2,4,5,6,4,3,2)
$mode(2,4,5,3,2,4,5,6,4,3,2)$
Similar Problems from Web Search
mn+1 \equiv 0 \pmod{24} then : m+n \equiv 0 \pmod{24} using group theory
$mn+1≡0(mod24)$
then :
$m+n≡0(mod24)$
using group theory
https://math.stackexchange.com/questions/2350421/mn1-equiv-0-pmod24-then-mn-equiv-0-pmod24-using-group-theory
You're trying to prove that if mn \equiv -1 \pmod{24} then m \equiv -n \pmod{24}. Let k = -n. Then you're trying to show that if -mk \equiv -1 \pmod{24} then m \equiv k \pmod{24}. Of ...
You're trying to prove that if
$mn≡−1(mod24)$
then
$m≡−n(mod24)$
. Let
$k=−n$
. Then you're trying to show that if
$−mk≡−1(mod24)$
then
$m≡k(mod24)$
. Of ...
Can we ever have \Gamma \models \perp
Can we ever have
$Γ⊨⊥$
https://math.stackexchange.com/questions/2639449/can-we-ever-have-gamma-models-perp
That's exactly right: "\Gamma\models\perp" is equivalent to "\Gamma has no model" (or "\Gamma is unsatisfiable").
That's exactly right: "
$Γ⊨⊥$
" is equivalent to "
$Γ$
has no model" (or "
$Γ$
is unsatisfiable").
Is this proof about Mersenne numbers acceptable?
Is this proof about Mersenne numbers acceptable?
https://math.stackexchange.com/questions/86429/is-this-proof-about-mersenne-numbers-acceptable
There is nothing incorrect, but there are a few things that could be changed. We only need p>2. From 2^p \equiv 2 \pmod {p} one should conclude M_p=2^p -1\equiv 1 \pmod{p} immediately, without ...
There is nothing incorrect, but there are a few things that could be changed. We only need
$p>2$
. From
$2_{p}≡2(modp)$
one should conclude
$M_{p}=2_{p}−1≡1(modp)$
immediately, without ...
Solving system of linear congruence equations
Solving system of linear congruence equations
https://math.stackexchange.com/questions/473711/solving-system-of-linear-congruence-equations
The way you express your congruences is rather unconventional. Given that 23d\equiv1\pmod{40}, 73d\equiv1\pmod{102}, and that 40=2^3\times5 and 102=2\times3\times17, it follows that 23d\equiv1\pmod5, ...
The way you express your congruences is rather unconventional. Given that
$23d≡1(mod40),$
$73d≡1(mod102),$
and that
$40=2_{3}×5$
and
$102=2×3×17$
, it follows that
$23d≡1(mod5),$
...
How to prove an element of a given structure is not definable?
How to prove an element of a given structure is not definable?
https://math.stackexchange.com/questions/927915/how-to-prove-an-element-of-a-given-structure-is-not-definable
HINT: If x is a definable element in a structure \mathcal M, then any automorphism of \cal M must satisfy f(x)=x. To show that 2 is not definable, find an automorphism of \cal A such that ...
HINT: If
$x$
is a definable element in a structure
$M$
, then any automorphism of
$M$
must satisfy
$f(x)=x$
. To show that
$2$
is not definable, find an automorphism of
$A$
such that ...
The deduction theorem according to AIMA
The deduction theorem according to AIMA
https://math.stackexchange.com/questions/13251/the-deduction-theorem-according-to-aima
In order for \alpha\Rightarrow\beta to be valid, it must hold in all models; for \alpha\Rightarrow\beta to not be valid, there must be a model where it is false. If there is a model where it is ...
In order for
$α⇒β$
to be valid, it must hold in all models; for
$α⇒β$
to not be valid, there must be a model where it is false. If there is a model where it is ...
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Similar Problems
mode(1,2,3,2,1,2,3)
$mode(1,2,3,2,1,2,3)$
mode(1,2,3)
$mode(1,2,3)$
mode(20,34,32,35,45,32,45,32,32)
$mode(20,34,32,35,45,32,45,32,32)$
mode(2,4,5,3,2,4,5,6,4,3,2)
$mode(2,4,5,3,2,4,5,6,4,3,2)$
mode(10,11,10,12)
$mode(10,11,10,12)$
mode(1,1,2,2,3,3)
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