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Topics
Pre-Algebra
Mean
Mode
Greatest Common Factor
Least Common Multiple
Order of Operations
Fractions
Mixed Fractions
Prime Factorization
Exponents
Radicals
Algebra
Combine Like Terms
Solve for a Variable
Factor
Expand
Evaluate Fractions
Linear Equations
Quadratic Equations
Inequalities
Systems of Equations
Matrices
Trigonometry
Simplify
Evaluate
Graphs
Solve Equations
Calculus
Derivatives
Integrals
Limits
Algebra Calculator
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Calculus Calculator
Matrix Calculator
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Evaluate
\frac{y^{9}}{3}
3
y
9
View solution steps
Solution Steps
\frac{x^3y^5}{3x} \times \frac{y^4}{x^2}
3
x
x
3
y
5
×
x
2
y
4
Cancel out x in both numerator and denominator.
Cancel out
x
in both numerator and denominator.
\frac{x^{2}y^{5}}{3}\times \left(\frac{y^{4}}{x^{2}}\right)
3
x
2
y
5
×
(
x
2
y
4
)
Multiply \frac{x^{2}y^{5}}{3} times \frac{y^{4}}{x^{2}} by multiplying numerator times numerator and denominator times denominator.
Multiply
3
x
2
y
5
times
x
2
y
4
by multiplying numerator times numerator and denominator times denominator.
\frac{x^{2}y^{5}y^{4}}{3x^{2}}
3
x
2
x
2
y
5
y
4
Cancel out x^{2} in both numerator and denominator.
Cancel out
x
2
in both numerator and denominator.
\frac{y^{4}y^{5}}{3}
3
y
4
y
5
To multiply powers of the same base, add their exponents. Add 4 and 5 to get 9.
To multiply powers of the same base, add their exponents. Add
4
and
5
to get
9
.
\frac{y^{9}}{3}
3
y
9
Differentiate w.r.t. y
3y^{8}
3
y
8
View solution steps
Steps Using Definition of a Derivative
\frac{x^3y^5}{3x} \times \frac{y^4}{x^2}
3
x
x
3
y
5
×
x
2
y
4
Cancel out x in both numerator and denominator.
Cancel out
x
in both numerator and denominator.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{x^{2}y^{5}}{3}\times \left(\frac{y^{4}}{x^{2}}\right))
d
y
d
(
3
x
2
y
5
×
(
x
2
y
4
)
)
Multiply \frac{x^{2}y^{5}}{3} times \frac{y^{4}}{x^{2}} by multiplying numerator times numerator and denominator times denominator.
Multiply
3
x
2
y
5
times
x
2
y
4
by multiplying numerator times numerator and denominator times denominator.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{x^{2}y^{5}y^{4}}{3x^{2}})
d
y
d
(
3
x
2
x
2
y
5
y
4
)
Cancel out x^{2} in both numerator and denominator.
Cancel out
x
2
in both numerator and denominator.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{y^{4}y^{5}}{3})
d
y
d
(
3
y
4
y
5
)
To multiply powers of the same base, add their exponents. Add 4 and 5 to get 9.
To multiply powers of the same base, add their exponents. Add
4
and
5
to get
9
.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{y^{9}}{3})
d
y
d
(
3
y
9
)
The derivative of ax^{n} is nax^{n-1}.
The derivative of
a
x
n
is
n
a
x
n
−
1
.
9\times \left(\frac{1}{3}\right)y^{9-1}
9
×
(
3
1
)
y
9
−
1
Multiply 9 times \frac{1}{3}.
Multiply
9
times
3
1
.
3y^{9-1}
3
y
9
−
1
Subtract 1 from 9.
Subtract
1
from
9
.
3y^{8}
3
y
8
Quiz
Algebra
5 problems similar to:
\frac{x^3y^5}{3x} \times \frac{y^4}{x^2}
3
x
x
3
y
5
×
x
2
y
4
Similar Problems from Web Search
How do you simplify \displaystyle{\left({\frac{{{2}{x}^{{{2}}}{y}}}{{{x}^{{{3}}}}}}\right)}^{{{3}}}\times{\left({\frac{{{y}^{{{1}}}}}{{{2}{x}}}}\right)}^{{-{2}}} ?
How do you simplify
(
x
3
2
x
2
y
)
3
×
(
2
x
y
1
)
−
2
?
https://socratic.org/questions/how-do-you-simplify-frac-2x-2-y-x-3-3-times-frac-y-1-2x-2
\displaystyle{32}{x}^{{-{{1}}}}{y} Explanation: Given, \displaystyle{\left[\frac{{{2}{x}^{{2}}{y}}}{{x}^{{3}}}\right]}^{{3}}.{\left[\frac{{y}^{{1}}}{{{2}{x}}}\right]}^{{-{{2}}}} \displaystyle\Rightarrow{\left[\frac{{{2}{y}}}{{x}}\right]}^{{3}}.{\left[\frac{{{2}{x}}}{{y}}\right]}^{{2}} ...
3
2
x
−
1
y
Explanation: Given,
[
x
3
2
x
2
y
]
3
.
[
2
x
y
1
]
−
2
⇒
[
x
2
y
]
3
.
[
y
2
x
]
2
...
How do you simplify \displaystyle\frac{{{3}{x}}}{{{6}{x}^{{2}}}}\times\frac{{{2}{y}-{6}}}{{{y}-{3}}} ?
How do you simplify
6
x
2
3
x
×
y
−
3
2
y
−
6
?
https://socratic.org/questions/how-do-you-simplify-3x-6x-2-times-2y-6-y-3
Konstantinos Michailidis May 26, 2016 It is \displaystyle\frac{{{3}{x}}}{{{6}{x}^{{2}}}}\times\frac{{{2}{y}-{6}}}{{{y}-{3}}}=\frac{{{3}{x}}}{{{2}{x}\cdot{3}{x}}}\times{\left(\frac{{{2}\cdot{\left({y}-{3}\right)}}}{{{y}-{3}}}\right)}=\frac{{\cancel{{{3}{x}}}}}{{{2}{x}\cdot\cancel{{{3}{x}}}}}\times{\left(\frac{{{2}\cdot\cancel{{{y}-{3}}}}}{\cancel{{{y}-{3}}}}\right)}=\frac{{1}}{{{2}{x}}}\times{2}=\frac{{1}}{{\cancel{{2}}\cdot{x}}}\cdot\cancel{{2}}=\frac{{1}}{{x}}
Konstantinos Michailidis May 26, 2016 It is
6
x
2
3
x
×
y
−
3
2
y
−
6
=
2
x
⋅
3
x
3
x
×
(
y
−
3
2
⋅
(
y
−
3
)
)
=
2
x
⋅
3
x
3
x
×
(
y
−
3
2
⋅
y
−
3
)
=
2
x
1
×
2
=
2
⋅
x
1
⋅
2
=
x
1
Can someone help me simplify this please? \displaystyle\frac{{{x}^{{2}}-{y}^{{2}}}}{{y}^{{2}}}\times\frac{{y}^{{3}}}{{{y}-{x}}}
Can someone help me simplify this please?
y
2
x
2
−
y
2
×
y
−
x
y
3
https://socratic.org/questions/can-someone-help-me-simplify-this-please-2
\displaystyle-{y}{\left({x}+{y}\right)} Explanation: \displaystyle{x}^{{2}}-{y}^{{2}}\ \text{ is a }\ \text{difference of squares} \displaystyle\text{and factors in general as} \displaystyle•{\left({x}\right)}{a}^{{2}}-{b}^{{2}}={\left({a}-{b}\right)}{\left({a}+{b}\right)} ...
−
y
(
x
+
y
)
Explanation:
x
2
−
y
2
is a
difference of squares
and factors in general as
•
(
x
)
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
...
How do you simplify \displaystyle{\left(-\frac{{8}}{{21}}{x}^{{2}}{y}^{{3}}\right)}\times{\left(-\frac{{7}}{{16}}{x}{y}^{{2}}\right)} ?
How do you simplify
(
−
2
1
8
x
2
y
3
)
×
(
−
1
6
7
x
y
2
)
?
https://socratic.org/questions/how-do-you-simplify-8-21-x-2y-3-times-7-16xy-2
See a solution process below: Explanation: First, rewrite the expression as: \displaystyle{\left(-\frac{{8}}{{21}}\times-\frac{{7}}{{16}}\right)}{\left({x}^{{2}}\times{x}\right)}{\left({y}^{{3}}\times{y}^{{2}}\right)}\Rightarrow ...
See a solution process below: Explanation: First, rewrite the expression as:
(
−
2
1
8
×
−
1
6
7
)
(
x
2
×
x
)
(
y
3
×
y
2
)
⇒
...
How do you simplify \displaystyle{\left(\frac{{{2}{x}^{{-{{1}}}}}}{{\left({3}{y}^{{2}}\right)}^{{2}}}\right)}\times\frac{{{3}{x}^{{2}}}}{{{5}{y}}} ?
How do you simplify
(
(
3
y
2
)
2
2
x
−
1
)
×
5
y
3
x
2
?
https://socratic.org/questions/how-do-you-simplify-2x-1-3y-2-2-times-3x-2-5y
\displaystyle\frac{{{6}{x}}}{{{45}{y}^{{5}}}} Every step shown to aid understanding. As you become practised you will be able to skip steps. Explanation: Splitting the given expression down into ...
4
5
y
5
6
x
Every step shown to aid understanding. As you become practised you will be able to skip steps. Explanation: Splitting the given expression down into ...
Are these two rings isomorphic? And can I use the chinese remainder theorem to prove it?
Are these two rings isomorphic? And can I use the chinese remainder theorem to prove it?
https://math.stackexchange.com/questions/2675475/are-these-two-rings-isomorphic-and-can-i-use-the-chinese-remainder-theorem-to-p
Assume that \text{char} k \neq 2. If x²+1 is irreducible over k one has that k[x,y]/(x²+1,y²+1) \simeq k(i)[y]/(y²+1). Since in k(i)[y] one has (y²+1) = (y+i)(y-i) and since (y+i) - (y-i) = 2i \in k(i)^\times ...
Assume that
char
k
=
2
. If
x
²
+
1
is irreducible over
k
one has that
k
[
x
,
y
]
/
(
x
²
+
1
,
y
²
+
1
)
≃
k
(
i
)
[
y
]
/
(
y
²
+
1
)
. Since in
k
(
i
)
[
y
]
one has
(
y
²
+
1
)
=
(
y
+
i
)
(
y
−
i
)
and since
(
y
+
i
)
−
(
y
−
i
)
=
2
i
∈
k
(
i
)
×
...
More Items
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\frac{x^{2}y^{5}}{3}\times \left(\frac{y^{4}}{x^{2}}\right)
Cancel out x in both numerator and denominator.
\frac{x^{2}y^{5}y^{4}}{3x^{2}}
Multiply \frac{x^{2}y^{5}}{3} times \frac{y^{4}}{x^{2}} by multiplying numerator times numerator and denominator times denominator.
\frac{y^{4}y^{5}}{3}
Cancel out x^{2} in both numerator and denominator.
\frac{y^{9}}{3}
To multiply powers of the same base, add their exponents. Add 4 and 5 to get 9.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{x^{2}y^{5}}{3}\times \left(\frac{y^{4}}{x^{2}}\right))
Cancel out x in both numerator and denominator.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{x^{2}y^{5}y^{4}}{3x^{2}})
Multiply \frac{x^{2}y^{5}}{3} times \frac{y^{4}}{x^{2}} by multiplying numerator times numerator and denominator times denominator.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{y^{4}y^{5}}{3})
Cancel out x^{2} in both numerator and denominator.
\frac{\mathrm{d}}{\mathrm{d}y}(\frac{y^{9}}{3})
To multiply powers of the same base, add their exponents. Add 4 and 5 to get 9.
9\times \left(\frac{1}{3}\right)y^{9-1}
The derivative of ax^{n} is nax^{n-1}.
3y^{9-1}
Multiply 9 times \frac{1}{3}.
3y^{8}
Subtract 1 from 9.
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\frac{x^3y^5}{3x} \times \frac{y^4}{x^2}
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\frac{x^3y^5}{3x} \div \frac{y^4}{x^2}
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