Επίλυση tanθ-3cotθ=2tan3θ

$$\tan \theta - 3 \cot \theta = 2 \tan 3 \theta$$

Λύση ως προς θ

$$\theta =\frac{4}{3}\pi +2\pi n_{106}\text{, }n_{106}\in \mathrm{Z}$$

$$\theta =\frac{5}{3}\pi +2\pi n_{119}\text{, }n_{119}\in \mathrm{Z}$$

$$\theta =\frac{2}{3}\pi +2\pi n_{132}\text{, }n_{132}\in \mathrm{Z}$$

$$\theta =\frac{1}{3}\pi +2\pi n_{145}\text{, }n_{145}\in \mathrm{Z}$$

$$\theta =\frac{5}{4}\pi +2\pi n_{88}\text{, }n_{88}\in \mathrm{Z}$$

$$\theta =\frac{7}{4}\pi +2\pi n_{87}\text{, }n_{87}\in \mathrm{Z}$$

$$\theta =\frac{3}{4}\pi +2\pi n_{94}\text{, }n_{94}\in \mathrm{Z}$$

$$\theta =\frac{1}{4}\pi +2\pi n_{93}\text{, }n_{93}\in \mathrm{Z}$$