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Sjov + forbedring af færdigheder = vinde!
Emner
Præ-Algebra
Betyde
Tilstand
Største fælles faktor
Mindst almindelige multiplum
Rækkefølgen af operationer
Fraktioner
Blandede brøker
Prime Factorization
Eksponenter
Radikaler
Algebra
Kombiner lignende udtryk
Løs for en variabel
Faktor
Ekspandere
Vurder brøker
Lineære ligninger
Kvadratiske ligninger
Uligheder
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Løs for x
x=\frac{2\pi n_{1}}{3}+\frac{2\pi }{9}\text{, }n_{1}\in \mathrm{Z}
x=\frac{2\pi n_{1}}{3}+\frac{4\pi }{9}\text{, }n_{1}\in \mathrm{Z}
Graf
Fremstil begge sider grafisk i 2D
Fremstil grafisk i 2D
Quiz
Trigonometry
\cos ( 3x + \pi ) = 0.5
Lignende problemer fra websøgning
How do you prove the reduction identities \displaystyle{\cos{{\left({x}+\pi\right)}}}=-{\cos{{\left({x}\right)}}} using a unit circle diagram?
https://socratic.org/questions/how-do-you-prove-the-reduction-identities-cos-x-pi-cos-x-using-a-unit-circle-dia
I am not sure this little diagram is enough but... Explanation: Have a look:
How to find all solutions of \cos (3x) + \cos (x) = 0 in [-\pi,\pi]
https://www.quora.com/How-do-I-find-all-solutions-of-cos-3x-+-cos-x-0-in-pi-pi
cos 3x+cos x=0 =>2 cos 2x cos x=0 =>cos 2x=0; or ; cos x=0 For x belong to[-pi,pi]; cos x=0 =>x = pi/2 , -pi/2 , 3 pi/2 , -3 pi/2 ...
How do you find the range of \displaystyle{f{{\left({x}\right)}}}={5}{\cos{{\left({x}+\pi\right)}}}+{3} ?
https://socratic.org/questions/how-do-you-find-the-range-of-f-x-5cos-x-pi-3
Alan P. Apr 15, 2015 \displaystyle{\cos{{\left({x}+\pi\right)}}} has a range of \displaystyle{\left[-{1},+{1}\right]} (because \displaystyle{\cos{{(}}} anything \displaystyle{)} ...
How to solve 0=\cos{2x}+\cos x
https://math.stackexchange.com/questions/859100/how-to-solve-0-cos2x-cos-x
remember the identity \cos (2x)=\cos^2 (x)-\sin^2(x)=2\cos ^2 (x)-1. You want to solve 2\cos ^2 (x)-1+\cos (x)=0. Let t= \cos (x). The question 2t^2+t-1=0 and is easier to solve. Can you take ...
How do you simplify \displaystyle{2}{\cos{{\left({10}{x}\right)}}}+{4}{\cos{{\left({5}{x}\right)}}} ?
https://socratic.org/questions/how-do-you-simplify-2cos-10x-4cos-5x
Simplify y = 2cos (10x) + 4cos (5x) Ans: (cos 5x - 1 - sqrt3)(cos 5x + 1 - sqrt3) Explanation: Replace 2cos (10x) by \displaystyle{4}{{\cos}^{{2}}{\left({5}{x}\right)}}-{2} , we get: y = 4cos^2 ...
How do you solve \displaystyle{\cos{{\left({x}\right)}}}{\left({\cos{{\left({x}\right)}}}-{1}\right)}={0} ?
https://socratic.org/questions/how-do-you-solve-cos-x-cos-x-1-0
\displaystyle{x}={0}+{2}{k}\pi\ \text{ or }\ {x}=\pi+{2}{k}\pi Explanation: \displaystyle{\left({\cos{{x}}}\right)}{\left({\cos{{x}}}\right)}-{1}={0}\ \text{ can be expressed as} \displaystyle{{\cos}^{{2}}{x}}={1} ...
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Lignende problemer
\cos ( 3x + \pi ) = 0.5
\sin ( x ) = 1
\sin ( x ) - cos ( x ) = 0
\sin ( x ) + 2 = 3
{ \tan ( x ) } ^ {2} = 4
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