Datrys y=2pisqrt{L/32}

$$y = 2 \pi \sqrt { \frac { L } { 32 } }$$

Datrys ar gyfer L

$$L=8\times \left(\frac{y}{\pi }\right)^{2}$$

$$y\geq 0$$

Camau ar gyfer Datrys Hafaliadau Radical

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$2\pi \sqrt{\frac{L}{32}}=y$$

Rhannu’r ddwy ochr â 2\pi .

$$\frac{2\pi \sqrt{\frac{1}{32}L}}{2\pi }=\frac{y}{2\pi }$$

Mae rhannu â 2\pi yn dad-wneud lluosi â 2\pi .

$$\sqrt{\frac{1}{32}L}=\frac{y}{2\pi }$$

Sgwariwch ddwy ochr yr hafaliad.

$$\frac{1}{32}L=\frac{y^{2}}{4\pi ^{2}}$$

Lluosi’r ddwy ochr â 32.

$$\frac{\frac{1}{32}L}{\frac{1}{32}}=\frac{y^{2}}{\frac{1}{32}\times 4\pi ^{2}}$$

Mae rhannu â \frac{1}{32} yn dad-wneud lluosi â \frac{1}{32}.

$$L=\frac{y^{2}}{\frac{1}{32}\times 4\pi ^{2}}$$

Rhannwch \frac{y^{2}}{4\pi ^{2}} â \frac{1}{32} drwy luosi \frac{y^{2}}{4\pi ^{2}} â chilydd \frac{1}{32}.

$$L=\frac{8y^{2}}{\pi ^{2}}$$

Datrys ar gyfer L (complex solution)

$$L=8\times \left(\frac{y}{\pi }\right)^{2}$$

$$|\frac{arg(y^{2})}{2}-arg(y)|<\pi \text{ or }y=0$$

Datrys ar gyfer y (complex solution)

$$y=\frac{\pi \sqrt{2L}}{4}$$

Datrys ar gyfer y

$$y=\frac{\pi \sqrt{2L}}{4}$$

$$L\geq 0$$