Datrys y=sqrt{2x-4}-1

$$y = \sqrt{ 2x-4 } -1$$

Datrys ar gyfer x

$$x=\frac{\left(y+1\right)^{2}+4}{2}$$

$$y+1\geq 0$$

Camau ar gyfer Datrys Hafaliadau Radical

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$\sqrt{2x-4}-1=y$$

Ychwanegu 1 at y ddwy ochr.

$$\sqrt{2x-4}=y+1$$

Sgwariwch ddwy ochr yr hafaliad.

$$2x-4=\left(y+1\right)^{2}$$

Adio 4 at ddwy ochr yr hafaliad.

$$2x-4-\left(-4\right)=\left(y+1\right)^{2}-\left(-4\right)$$

Mae tynnu -4 o’i hun yn gadael 0.

$$2x=\left(y+1\right)^{2}-\left(-4\right)$$

Tynnu -4 o \left(y+1\right)^{2}.

$$2x=\left(y+1\right)^{2}+4$$

Rhannu’r ddwy ochr â 2.

$$\frac{2x}{2}=\frac{\left(y+1\right)^{2}+4}{2}$$

Mae rhannu â 2 yn dad-wneud lluosi â 2.

$$x=\frac{\left(y+1\right)^{2}+4}{2}$$

Rhannwch \left(y+1\right)^{2}+4 â 2.

$$x=\frac{\left(y+1\right)^{2}}{2}+2$$

Datrys ar gyfer x (complex solution)

$$x=\frac{\left(y+1\right)^{2}+4}{2}$$

$$y=-1\text{ or }arg(y+1)<\pi$$

Datrys ar gyfer y (complex solution)

$$y=\sqrt{2\left(x-2\right)}-1$$

Datrys ar gyfer y

$$y=\sqrt{2\left(x-2\right)}-1$$

$$x\geq 2$$