Datrys x^0=frac{30+4^2+sqrt{8}1+5^2x5}{4x+15+2(6-5)}

$$x ^ { 0 } = \frac { 30 + 4 ^ { 2 } + \sqrt { 8 } 1 + 5 ^ { 2 } x 5 } { 4 x + 15 + 2 ( 6 - 5 ) }$$

Datrys ar gyfer x_5

$$x_{5}=\frac{4x-2\sqrt{2}-29}{25}$$

$$x\neq 0\text{ and }x\neq -\frac{17}{4}$$

Camau ar gyfer Datrys Hafaliad Llinol

Lluoswch ddwy ochr yr hafaliad â 4x+17.

$$\left(4x+17\right)x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

Defnyddio’r briodwedd ddosbarthu i luosi 4x+17 â x^{0}.

$$4xx^{0}+17x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

Er mwyn lluosi pwerau sy’n rhannu’r un sail, adiwch eu esbonyddion. Adiwch 1 a 0 i gael 1.

$$4x^{1}+17x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

Cyfrifo x i bŵer 1 a chael x.

$$4x+17x^{0}=30+4^{2}+1\sqrt{8}+5^{2}x_{5}$$

Cyfrifo 4 i bŵer 2 a chael 16.

$$4x+17x^{0}=30+16+1\sqrt{8}+5^{2}x_{5}$$

Adio 30 a 16 i gael 46.

$$4x+17x^{0}=46+1\sqrt{8}+5^{2}x_{5}$$

Ffactora 8=2^{2}\times 2. Ailysgrifennu ail isradd y lluoswm \sqrt{2^{2}\times 2} fel lluoswm ail israddau \sqrt{2^{2}}\sqrt{2}. Cymryd isradd 2^{2}.

$$4x+17x^{0}=46+1\times 2\sqrt{2}+5^{2}x_{5}$$

Lluosi 1 a 2 i gael 2.

$$4x+17x^{0}=46+2\sqrt{2}+5^{2}x_{5}$$

Cyfrifo 5 i bŵer 2 a chael 25.

$$4x+17x^{0}=46+2\sqrt{2}+25x_{5}$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$46+2\sqrt{2}+25x_{5}=4x+17x^{0}$$

Tynnu 46 o'r ddwy ochr.

$$2\sqrt{2}+25x_{5}=4x+17x^{0}-46$$

Tynnu 2\sqrt{2} o'r ddwy ochr.

$$25x_{5}=4x+17x^{0}-46-2\sqrt{2}$$

Mae'r hafaliad yn y ffurf safonol.

$$25x_{5}=4x-2\sqrt{2}-29$$

Rhannu’r ddwy ochr â 25.

$$\frac{25x_{5}}{25}=\frac{4x-2\sqrt{2}-29}{25}$$

Mae rhannu â 25 yn dad-wneud lluosi â 25.

$$x_{5}=\frac{4x-2\sqrt{2}-29}{25}$$

Datrys ar gyfer x (complex solution)

$$x=\frac{25x_{5}}{4}+\frac{\sqrt{2}}{2}+\frac{29}{4}$$

$$x_{5}\neq \frac{-2\sqrt{2}-29}{25}\text{ and }x_{5}\neq \frac{-2\sqrt{2}-46}{25}\text{ and }x_{5}\neq \frac{-2\sqrt{2}-29}{25}$$

Datrys ar gyfer x

$$x=\frac{25x_{5}}{4}+\frac{\sqrt{2}}{2}+\frac{29}{4}$$

$$x_{5}\neq \frac{-2\sqrt{2}-29}{25}\text{ and }x_{5}\neq \frac{-2\sqrt{2}-46}{25}$$