Datrys f(x)^2/3+(mn^2)^2/3=1

$$f ( x ) ^ { 2 / 3 } + ( m n ^ { 2 } ) ^ { 2 / 3 } = 1$$

Datrys ar gyfer f

$$\left\{\begin{matrix}f=-\frac{m^{\frac{2}{3}}n^{\frac{4}{3}}-1}{x^{\frac{2}{3}}}\text{, }&x\neq 0\\f\in \mathrm{R}\text{, }&n\neq 0\text{ and }x=0\text{ and }|m|=\frac{1}{n^{2}}\end{matrix}\right.$$

Camau ar gyfer Datrys Hafaliad Llinol

Ehangu \left(mn^{2}\right)^{\frac{2}{3}}.

$$fx^{\frac{2}{3}}+m^{\frac{2}{3}}\left(n^{2}\right)^{\frac{2}{3}}=1$$

I godi pŵer rhif i bŵer arall, lluoswch yr esbonyddion. Lluoswch 2 a \frac{2}{3} i gael \frac{4}{3}.

$$fx^{\frac{2}{3}}+m^{\frac{2}{3}}n^{\frac{4}{3}}=1$$

Tynnu m^{\frac{2}{3}}n^{\frac{4}{3}} o'r ddwy ochr.

$$fx^{\frac{2}{3}}=1-m^{\frac{2}{3}}n^{\frac{4}{3}}$$

Aildrefnu'r termau.

$$x^{\frac{2}{3}}f=-m^{\frac{2}{3}}n^{\frac{4}{3}}+1$$

Mae'r hafaliad yn y ffurf safonol.

$$x^{\frac{2}{3}}f=1-m^{\frac{2}{3}}n^{\frac{4}{3}}$$

Rhannu’r ddwy ochr â x^{\frac{2}{3}}.

$$\frac{x^{\frac{2}{3}}f}{x^{\frac{2}{3}}}=\frac{1-m^{\frac{2}{3}}n^{\frac{4}{3}}}{x^{\frac{2}{3}}}$$

Mae rhannu â x^{\frac{2}{3}} yn dad-wneud lluosi â x^{\frac{2}{3}}.

$$f=\frac{1-m^{\frac{2}{3}}n^{\frac{4}{3}}}{x^{\frac{2}{3}}}$$

Datrys ar gyfer m

$$\left\{\begin{matrix}m=-\frac{1}{n^{2}}\text{; }m=\frac{1}{n^{2}}\text{, }&x=0\text{ and }n\neq 0\\m\in \mathrm{R}\text{, }&f=\frac{1}{x^{\frac{2}{3}}}\text{ and }n=0\text{ and }x\neq 0\\m=-\frac{\left(1-x^{\frac{2}{3}}f\right)^{\frac{3}{2}}}{n^{2}}\text{; }m=\frac{\left(1-x^{\frac{2}{3}}f\right)^{\frac{3}{2}}}{n^{2}}\text{, }&n\neq 0\text{ and }f\leq \frac{1}{x^{\frac{2}{3}}}\text{ and }x\neq 0\end{matrix}\right.$$