Datrys f(x)=1/8(x+1)(x-5)^2

$$f ( x ) = \frac { 1 } { 8 } ( x + 1 ) ( x - 5 ) ^ { 2 }$$

Enrhifo

$$\frac{\left(x+1\right)\left(x-5\right)^{2}}{8}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(x-5\right)^{2}.

$$\frac{1}{8}\left(x+1\right)\left(x^{2}-10x+25\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi \frac{1}{8} â x+1.

$$\left(\frac{1}{8}x+\frac{1}{8}\right)\left(x^{2}-10x+25\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi \frac{1}{8}x+\frac{1}{8} â x^{2}-10x+25 a chyfuno termau tebyg.

$$\frac{1}{8}x^{3}-\frac{9}{8}x^{2}+\frac{15}{8}x+\frac{25}{8}$$

Ehangu

$$\frac{x^{3}-9x^{2}+15x+25}{8}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(x-5\right)^{2}.

$$\frac{1}{8}\left(x+1\right)\left(x^{2}-10x+25\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi \frac{1}{8} â x+1.

$$\left(\frac{1}{8}x+\frac{1}{8}\right)\left(x^{2}-10x+25\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi \frac{1}{8}x+\frac{1}{8} â x^{2}-10x+25 a chyfuno termau tebyg.

$$\frac{1}{8}x^{3}-\frac{9}{8}x^{2}+\frac{15}{8}x+\frac{25}{8}$$