Datrys 6x(x-1)^2-3x*(x+1)^2

$$6 x ( x - 1 ) ^ { 2 } - 3 x \cdot ( x + 1 ) ^ { 2 }$$

Enrhifo

$$3x\left(x^{2}-6x+1\right)$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(x-1\right)^{2}.

$$6x\left(x^{2}-2x+1\right)-3x\left(x+1\right)^{2}$$

Defnyddio’r briodwedd ddosbarthu i luosi 6x â x^{2}-2x+1.

$$6x^{3}-12x^{2}+6x-3x\left(x+1\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(x+1\right)^{2}.

$$6x^{3}-12x^{2}+6x-3x\left(x^{2}+2x+1\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi -3x â x^{2}+2x+1.

$$6x^{3}-12x^{2}+6x-3x^{3}-6x^{2}-3x$$

Cyfuno 6x^{3} a -3x^{3} i gael 3x^{3}.

$$3x^{3}-12x^{2}+6x-6x^{2}-3x$$

Cyfuno -12x^{2} a -6x^{2} i gael -18x^{2}.

$$3x^{3}-18x^{2}+6x-3x$$

Cyfuno 6x a -3x i gael 3x.

$$3x^{3}-18x^{2}+3x$$

Ehangu

$$3x^{3}-18x^{2}+3x$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a-b\right)^{2}=a^{2}-2ab+b^{2} i ehangu'r \left(x-1\right)^{2}.

$$6x\left(x^{2}-2x+1\right)-3x\left(x+1\right)^{2}$$

Defnyddio’r briodwedd ddosbarthu i luosi 6x â x^{2}-2x+1.

$$6x^{3}-12x^{2}+6x-3x\left(x+1\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(x+1\right)^{2}.

$$6x^{3}-12x^{2}+6x-3x\left(x^{2}+2x+1\right)$$

Defnyddio’r briodwedd ddosbarthu i luosi -3x â x^{2}+2x+1.

$$6x^{3}-12x^{2}+6x-3x^{3}-6x^{2}-3x$$

Cyfuno 6x^{3} a -3x^{3} i gael 3x^{3}.

$$3x^{3}-12x^{2}+6x-6x^{2}-3x$$

Cyfuno -12x^{2} a -6x^{2} i gael -18x^{2}.

$$3x^{3}-18x^{2}+6x-3x$$

Cyfuno 6x a -3x i gael 3x.

$$3x^{3}-18x^{2}+3x$$