Datrys 4(p+q)^2-(2p+q)^2

$$4 ( p + q ) ^ { 2 } - ( 2 p + q ) ^ { 2 }$$

Enrhifo

$$q\left(4p+3q\right)$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(p+q\right)^{2}.

$$4\left(p^{2}+2pq+q^{2}\right)-\left(2p+q\right)^{2}$$

Defnyddio’r briodwedd ddosbarthu i luosi 4 â p^{2}+2pq+q^{2}.

$$4p^{2}+8pq+4q^{2}-\left(2p+q\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(2p+q\right)^{2}.

$$4p^{2}+8pq+4q^{2}-\left(4p^{2}+4pq+q^{2}\right)$$

I ddod o hyd i wrthwyneb 4p^{2}+4pq+q^{2}, dewch o hyd i wrthwyneb pob term.

$$4p^{2}+8pq+4q^{2}-4p^{2}-4pq-q^{2}$$

Cyfuno 4p^{2} a -4p^{2} i gael 0.

$$8pq+4q^{2}-4pq-q^{2}$$

Cyfuno 8pq a -4pq i gael 4pq.

$$4pq+4q^{2}-q^{2}$$

Cyfuno 4q^{2} a -q^{2} i gael 3q^{2}.

$$4pq+3q^{2}$$

Ehangu

$$4pq+3q^{2}$$

Camau Ateb

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(p+q\right)^{2}.

$$4\left(p^{2}+2pq+q^{2}\right)-\left(2p+q\right)^{2}$$

Defnyddio’r briodwedd ddosbarthu i luosi 4 â p^{2}+2pq+q^{2}.

$$4p^{2}+8pq+4q^{2}-\left(2p+q\right)^{2}$$

Defnyddio'r theorem binomaidd \left(a+b\right)^{2}=a^{2}+2ab+b^{2} i ehangu'r \left(2p+q\right)^{2}.

$$4p^{2}+8pq+4q^{2}-\left(4p^{2}+4pq+q^{2}\right)$$

I ddod o hyd i wrthwyneb 4p^{2}+4pq+q^{2}, dewch o hyd i wrthwyneb pob term.

$$4p^{2}+8pq+4q^{2}-4p^{2}-4pq-q^{2}$$

Cyfuno 4p^{2} a -4p^{2} i gael 0.

$$8pq+4q^{2}-4pq-q^{2}$$

Cyfuno 8pq a -4pq i gael 4pq.

$$4pq+4q^{2}-q^{2}$$

Cyfuno 4q^{2} a -q^{2} i gael 3q^{2}.

$$4pq+3q^{2}$$