Datrys 28=36e^-k10

$$28 = 36 e ^ { - k 10 }$$

Datrys ar gyfer k_10

$$k_{10}=\ln(\frac{9}{7})\approx 0.251314428$$

Camau gan Ddefnyddio Diffiniad Logarithm

Rhannu’r ddwy ochr â 36.

$$\frac{28}{36}=e^{-k_{10}}$$

Lleihau'r ffracsiwn \frac{28}{36} i'r graddau lleiaf posib drwy dynnu a chanslo allan 4.

$$\frac{7}{9}=e^{-k_{10}}$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$e^{-k_{10}}=\frac{7}{9}$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(e^{-k_{10}})=\log(\frac{7}{9})$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$-k_{10}\log(e)=\log(\frac{7}{9})$$

Rhannu’r ddwy ochr â \log(e).

$$-k_{10}=\frac{\log(\frac{7}{9})}{\log(e)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$-k_{10}=\log_{e}\left(\frac{7}{9}\right)$$

Rhannu’r ddwy ochr â -1.

$$k_{10}=\frac{\ln(\frac{7}{9})}{-1}$$

Datrys ar gyfer k_10 (complex solution)

$$k_{10}=-2\pi n_{1}i+\ln(\frac{9}{7})$$

$$n_{1}\in \mathrm{Z}$$