Datrys 25000*(1+0.03/365)^x=1000000

$$25000 \times ( 1 + \frac { 0.03 } { 365 } ) ^ { x } = 1000000$$

Datrys ar gyfer x

$$x=\log_{\frac{36503}{36500}}\left(40\right)\approx 44883.211106122$$

Camau gan Ddefnyddio Diffiniad Logarithm

Rhannu’r ddwy ochr â 25000.

$$\left(1+\frac{0.03}{365}\right)^{x}=\frac{1000000}{25000}$$

Rhannu 1000000 â 25000 i gael 40.

$$\left(1+\frac{0.03}{365}\right)^{x}=40$$

Ehangu \frac{0.03}{365} drwy luosi'r rhifiadur a'r enwadur gyda 100.

$$\left(1+\frac{3}{36500}\right)^{x}=40$$

Adio 1 a \frac{3}{36500} i gael \frac{36503}{36500}.

$$\left(\frac{36503}{36500}\right)^{x}=40$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(\left(\frac{36503}{36500}\right)^{x})=\log(40)$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$x\log(\frac{36503}{36500})=\log(40)$$

Rhannu’r ddwy ochr â \log(\frac{36503}{36500}).

$$x=\frac{\log(40)}{\log(\frac{36503}{36500})}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{\frac{36503}{36500}}\left(40\right)$$

Datrys ar gyfer x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(\frac{36503}{36500})}+\log_{\frac{36503}{36500}}\left(40\right)$$

$$n_{1}\in \mathrm{Z}$$