Datrys 23=40e^-0.2h

$$23 = 40 e ^ { - 0.2 h }$$

Datrys ar gyfer h

$$h=\ln(\frac{102400000}{6436343})\approx 2.766926191$$

Camau gan Ddefnyddio Diffiniad Logarithm

Rhannu’r ddwy ochr â 40.

$$\frac{23}{40}=e^{-0.2h}$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$e^{-0.2h}=\frac{23}{40}$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(e^{-0.2h})=\log(\frac{23}{40})$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$-0.2h\log(e)=\log(\frac{23}{40})$$

Rhannu’r ddwy ochr â \log(e).

$$-0.2h=\frac{\log(\frac{23}{40})}{\log(e)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$-0.2h=\log_{e}\left(\frac{23}{40}\right)$$

Lluosi’r ddwy ochr â -5.

$$h=\frac{\ln(\frac{23}{40})}{-0.2}$$