Datrys 2^2x+3=8

$$2 ^ { 2 x + 3 } = 8$$

Datrys ar gyfer x

$$x=0$$

Camau gan Ddefnyddio Diffiniad Logarithm

Defnyddio rheolau esbonyddion a logarithmau i ddatrys yr hafaliad.

$$2^{2x+3}=8$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(2^{2x+3})=\log(8)$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$\left(2x+3\right)\log(2)=\log(8)$$

Rhannu’r ddwy ochr â \log(2).

$$2x+3=\frac{\log(8)}{\log(2)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2x+3=\log_{2}\left(8\right)$$

Tynnu 3 o ddwy ochr yr hafaliad.

$$2x=3-3$$

Rhannu’r ddwy ochr â 2.

$$x=\frac{0}{2}$$

Datrys ar gyfer x (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(2)}$$

$$n_{1}\in \mathrm{Z}$$