Datrys 18*2^x=2

$$18 \cdot 2 ^ { x } = 2$$

Datrys ar gyfer x

$$x=-2\log_{2}\left(3\right)\approx -3.169925001$$

Camau gan Ddefnyddio Diffiniad Logarithm

Defnyddio rheolau esbonyddion a logarithmau i ddatrys yr hafaliad.

$$18\times 2^{x}=2$$

Rhannu’r ddwy ochr â 18.

$$2^{x}=\frac{1}{9}$$

Cymryd logarithm dwy ochr yr hafaliad.

$$\log(2^{x})=\log(\frac{1}{9})$$

Logarithm rhif wedi’i godi i bŵer yw’r pŵer wedi’i lluosi â logarithm y rhif.

$$x\log(2)=\log(\frac{1}{9})$$

Rhannu’r ddwy ochr â \log(2).

$$x=\frac{\log(\frac{1}{9})}{\log(2)}$$

Gyda’r fformiwla newid-sail \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{2}\left(\frac{1}{9}\right)$$

Datrys ar gyfer x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(2)}-2\log_{2}\left(3\right)$$

$$n_{1}\in \mathrm{Z}$$