Datrys 161V=188v*frac{R_{1}}{R_{1}+21Omega}

$$161 V = 188 v \cdot \frac { R _ { 1 } } { R _ { 1 } + 21 \Omega }$$

Datrys ar gyfer V

$$V=\frac{188R_{1}v}{161\left(R_{1}+21\Omega \right)}$$

$$R_{1}\neq -21\Omega$$

Camau ar gyfer Datrys Hafaliad Llinol

Lluoswch ddwy ochr yr hafaliad â R_{1}+21\Omega .

$$161V\left(R_{1}+21\Omega \right)=188vR_{1}$$

Defnyddio’r briodwedd ddosbarthu i luosi 161V â R_{1}+21\Omega .

$$161VR_{1}+3381\Omega V=188vR_{1}$$

Cyfuno pob term sy'n cynnwys V.

$$\left(161R_{1}+3381\Omega \right)V=188vR_{1}$$

Mae'r hafaliad yn y ffurf safonol.

$$\left(161R_{1}+3381\Omega \right)V=188R_{1}v$$

Rhannu’r ddwy ochr â 161R_{1}+3381\Omega .

$$\frac{\left(161R_{1}+3381\Omega \right)V}{161R_{1}+3381\Omega }=\frac{188R_{1}v}{161R_{1}+3381\Omega }$$

Mae rhannu â 161R_{1}+3381\Omega yn dad-wneud lluosi â 161R_{1}+3381\Omega .

$$V=\frac{188R_{1}v}{161R_{1}+3381\Omega }$$

Rhannwch 188vR_{1} â 161R_{1}+3381\Omega .

$$V=\frac{188R_{1}v}{161\left(R_{1}+21\Omega \right)}$$

Datrys ar gyfer R_1

$$\left\{\begin{matrix}R_{1}=\frac{3381V\Omega }{188v-161V}\text{, }&\Omega \neq 0\text{ and }v\neq 0\text{ and }V\neq \frac{188v}{161}\\R_{1}\neq 0\text{, }&\Omega =0\text{ and }v=\frac{161V}{188}\text{ and }V\neq 0\\R_{1}\neq -21\Omega \text{, }&V=0\text{ and }v=0\end{matrix}\right.$$