Datrys 161V=188V*frac{R_{1}}{R_{1}+21Omega_{2}}

$$161 V = 188 V \cdot \frac { R _ { 1 } } { R _ { 1 } + 21 \Omega _ { 2 } }$$

Datrys ar gyfer V

$$\left\{\begin{matrix}V=0\text{, }&R_{1}\neq -21\Omega _{2}\\V\in \mathrm{R}\text{, }&R_{1}=\frac{1127\Omega _{2}}{9}\text{ and }\Omega _{2}\neq 0\end{matrix}\right.$$

Camau ar gyfer Datrys Hafaliad Llinol

Lluoswch ddwy ochr yr hafaliad â R_{1}+21\Omega _{2}.

$$161V\left(R_{1}+21\Omega _{2}\right)=188VR_{1}$$

Defnyddio’r briodwedd ddosbarthu i luosi 161V â R_{1}+21\Omega _{2}.

$$161VR_{1}+3381V\Omega _{2}=188VR_{1}$$

Tynnu 188VR_{1} o'r ddwy ochr.

$$161VR_{1}+3381V\Omega _{2}-188VR_{1}=0$$

Cyfuno 161VR_{1} a -188VR_{1} i gael -27VR_{1}.

$$-27VR_{1}+3381V\Omega _{2}=0$$

Cyfuno pob term sy'n cynnwys V.

$$\left(-27R_{1}+3381\Omega _{2}\right)V=0$$

Mae'r hafaliad yn y ffurf safonol.

$$\left(3381\Omega _{2}-27R_{1}\right)V=0$$

Rhannwch 0 â -27R_{1}+3381\Omega _{2}.

$$V=0$$

Datrys ar gyfer R_1

$$\left\{\begin{matrix}R_{1}=\frac{1127\Omega _{2}}{9}\text{, }&\Omega _{2}\neq 0\\R_{1}\neq -21\Omega _{2}\text{, }&V=0\end{matrix}\right.$$