Datrys 16.1V=18.8v*frac{R_{1}}{R_{1}+21Omega}

$$16.1 V = 18.8 v \cdot \frac { R _ { 1 } } { R _ { 1 } + 21 \Omega }$$

Datrys ar gyfer V

$$V=\frac{94R_{1}v}{5\times \frac{161R_{1}+3381\Omega }{10}}$$

$$R_{1}\neq -21\Omega$$

Camau ar gyfer Datrys Hafaliad Llinol

Lluoswch ddwy ochr yr hafaliad â R_{1}+21\Omega .

$$16.1V\left(R_{1}+21\Omega \right)=18.8vR_{1}$$

Defnyddio’r briodwedd ddosbarthu i luosi 16.1V â R_{1}+21\Omega .

$$16.1VR_{1}+338.1\Omega V=18.8vR_{1}$$

Cyfuno pob term sy'n cynnwys V.

$$\left(16.1R_{1}+338.1\Omega \right)V=18.8vR_{1}$$

Mae'r hafaliad yn y ffurf safonol.

$$\frac{161R_{1}+3381\Omega }{10}V=\frac{94R_{1}v}{5}$$

Rhannu’r ddwy ochr â 16.1R_{1}+338.1\Omega .

$$\frac{10\times \frac{161R_{1}+3381\Omega }{10}V}{161R_{1}+3381\Omega }=\frac{94R_{1}v}{5\times \frac{161R_{1}+3381\Omega }{10}}$$

Mae rhannu â 16.1R_{1}+338.1\Omega yn dad-wneud lluosi â 16.1R_{1}+338.1\Omega .

$$V=\frac{94R_{1}v}{5\times \frac{161R_{1}+3381\Omega }{10}}$$

Datrys ar gyfer R_1

$$\left\{\begin{matrix}\\R_{1}\neq 0\text{, }&\text{unconditionally}\\R_{1}=\frac{3381V\Omega }{188v-161V}\text{, }&\Omega \neq 0\text{ and }v\neq 0\text{ and }V\neq \frac{188v}{161}\\R_{1}\neq -21\Omega \text{, }&V=0\text{ and }v=0\end{matrix}\right.$$