Datrys 100=F+F1.618+F2.618

$$100 = F+F1.618+F2.618$$

Datrys ar gyfer F

$$F=-\frac{309F_{1}}{500}-\frac{309F_{2}}{500}+100$$

Camau Ateb

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$F+F_{1}\times 0.618+F_{2}\times 0.618=100$$

Tynnu F_{1}\times 0.618 o'r ddwy ochr.

$$F+F_{2}\times 0.618=100-F_{1}\times 0.618$$

Tynnu F_{2}\times 0.618 o'r ddwy ochr.

$$F=100-F_{1}\times 0.618-F_{2}\times 0.618$$

Lluosi -1 a 0.618 i gael -0.618.

$$F=100-0.618F_{1}-F_{2}\times 0.618$$

Lluosi -1 a 0.618 i gael -0.618.

$$F=100-0.618F_{1}-0.618F_{2}$$

Datrys ar gyfer F_1

$$F_{1}=-\frac{500F}{309}-F_{2}+\frac{50000}{309}$$

Camau ar gyfer Datrys Hafaliad Llinol

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$F+F_{1}\times 0.618+F_{2}\times 0.618=100$$

Tynnu F o'r ddwy ochr.

$$F_{1}\times 0.618+F_{2}\times 0.618=100-F$$

Tynnu F_{2}\times 0.618 o'r ddwy ochr.

$$F_{1}\times 0.618=100-F-F_{2}\times 0.618$$

Lluosi -1 a 0.618 i gael -0.618.

$$F_{1}\times 0.618=100-F-0.618F_{2}$$

Mae'r hafaliad yn y ffurf safonol.

$$0.618F_{1}=-\frac{309F_{2}}{500}-F+100$$

Rhannu dwy ochr hafaliad â 0.618, sydd yr un peth â lluosi’r ddwy ochr â chilydd y ffracsiwn.

$$\frac{0.618F_{1}}{0.618}=\frac{-\frac{309F_{2}}{500}-F+100}{0.618}$$

Mae rhannu â 0.618 yn dad-wneud lluosi â 0.618.

$$F_{1}=\frac{-\frac{309F_{2}}{500}-F+100}{0.618}$$

Rhannwch 100-F-\frac{309F_{2}}{500} â 0.618 drwy luosi 100-F-\frac{309F_{2}}{500} â chilydd 0.618.

$$F_{1}=-\frac{500F}{309}-F_{2}+\frac{50000}{309}$$