Datrys (x+1)*(x+3)=x^2+13cm^2

$$( x + 1 ) \cdot ( x + 3 ) = x ^ { 2 } + 13 cm ^ { 2 }$$

Datrys ar gyfer c (complex solution)

$$\left\{\begin{matrix}c=\frac{4x+3}{13m^{2}}\text{, }&m\neq 0\\c\in \mathrm{C}\text{, }&x=-\frac{3}{4}\text{ and }m=0\end{matrix}\right.$$

Camau ar gyfer Datrys Hafaliad Llinol

Defnyddio’r briodwedd ddosbarthu i luosi x+1 â x+3 a chyfuno termau tebyg.

$$x^{2}+4x+3=x^{2}+13cm^{2}$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$x^{2}+13cm^{2}=x^{2}+4x+3$$

Tynnu x^{2} o'r ddwy ochr.

$$13cm^{2}=x^{2}+4x+3-x^{2}$$

Cyfuno x^{2} a -x^{2} i gael 0.

$$13cm^{2}=4x+3$$

Mae'r hafaliad yn y ffurf safonol.

$$13m^{2}c=4x+3$$

Rhannu’r ddwy ochr â 13m^{2}.

$$\frac{13m^{2}c}{13m^{2}}=\frac{4x+3}{13m^{2}}$$

Mae rhannu â 13m^{2} yn dad-wneud lluosi â 13m^{2}.

$$c=\frac{4x+3}{13m^{2}}$$

Datrys ar gyfer c

$$\left\{\begin{matrix}c=\frac{4x+3}{13m^{2}}\text{, }&m\neq 0\\c\in \mathrm{R}\text{, }&x=-\frac{3}{4}\text{ and }m=0\end{matrix}\right.$$

Camau ar gyfer Datrys Hafaliad Llinol

Defnyddio’r briodwedd ddosbarthu i luosi x+1 â x+3 a chyfuno termau tebyg.

$$x^{2}+4x+3=x^{2}+13cm^{2}$$

Cyfnewidiwch yr ochrau fel bod yr holl dermau newidiol ar yr ochr chwith.

$$x^{2}+13cm^{2}=x^{2}+4x+3$$

Tynnu x^{2} o'r ddwy ochr.

$$13cm^{2}=x^{2}+4x+3-x^{2}$$

Cyfuno x^{2} a -x^{2} i gael 0.

$$13cm^{2}=4x+3$$

Mae'r hafaliad yn y ffurf safonol.

$$13m^{2}c=4x+3$$

Rhannu’r ddwy ochr â 13m^{2}.

$$\frac{13m^{2}c}{13m^{2}}=\frac{4x+3}{13m^{2}}$$

Mae rhannu â 13m^{2} yn dad-wneud lluosi â 13m^{2}.

$$c=\frac{4x+3}{13m^{2}}$$

Datrys ar gyfer m (complex solution)

$$\left\{\begin{matrix}m=-\frac{ic^{-\frac{1}{2}}\sqrt{-52x-39}}{13}\text{; }m=\frac{ic^{-\frac{1}{2}}\sqrt{-52x-39}}{13}\text{, }&c\neq 0\\m\in \mathrm{C}\text{, }&x=-\frac{3}{4}\text{ and }c=0\end{matrix}\right.$$

Datrys ar gyfer m

$$\left\{\begin{matrix}m=\frac{\sqrt{\frac{13\left(4x+3\right)}{c}}}{13}\text{; }m=-\frac{\sqrt{\frac{13\left(4x+3\right)}{c}}}{13}\text{, }&\left(x\geq -\frac{3}{4}\text{ and }c>0\right)\text{ or }\left(x\leq -\frac{3}{4}\text{ and }c<0\right)\\m\in \mathrm{R}\text{, }&x=-\frac{3}{4}\text{ and }c=0\end{matrix}\right.$$